段階的に解決し、人工知能を使用せず、優れた仕事を行いますご支援ありがとうございましたSOLVE STEP BY STEP IN DIGITAL FORMATDON'T USE AI | DON'T USE AI DON'T USE AI DON'T USE AIShow that if a, b, c ER then:(a) a-b=-(b-a).(b) (a+b)(a-b)-a(a-b)+b(b-a) = 0.(c) a.b=0⇔a=0o6=0.(d) (-a)(c-d) = ad-ac.

Answered: Show that if a, b, c ER then: (a)…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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段階的に解決し、人工知能を使用せず、優れた仕事を行います
ご支援ありがとうございました
SOLVE STEP BY STEP IN DIGITAL FORMAT
DON'T USE AI | DON'T USE AI DON'T USE AI DON'T USE AI
Show that if a, b, c ER then:
(a) a-b=-(b-a).
(b) (a+b)(a-b)-a(a-b)+b(b-a) = 0.
(c) a.b=0⇔a=0o6=0.
(d) (-a)(c-d) = ad-ac.

Expert Solution

Step 1: Proof the first part (a)

To prove

$a minus b equals negative left parenthesis b minus a right parenthesis L. H. S equals a minus b T h e n space R. H. S equals negative left parenthesis b minus a right parenthesis equals negative b minus left parenthesis negative a right parenthesis equals negative b plus a equals a minus b T h u s space a minus b equals negative left parenthesis b minus a right parenthesis space space a comma b element of space R.$

Hence proved.