Show that every vector in T1 = span {(1,0,0); (0,1,0); (0,0,1)} are in also in T2 Та %3 span {(1,1,0); (0,0,1); (1,0,1)}, i.e. show explicitly how , in T2 corresponds to some given t, in T1.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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6. Show that every vector in \( T_1 = \text{span} \{ (1,0,0); (0,1,0); (0,0,1) \} \) are also in 

\[ T_2 = \text{span} \{ (1,1,0); (0,0,1); (1,0,1) \}, \]

i.e., show explicitly how \( \vec{t}_2 \) in \( T_2 \) corresponds to some given \( \vec{t}_1 \) in \( T_1 \).
Transcribed Image Text:6. Show that every vector in \( T_1 = \text{span} \{ (1,0,0); (0,1,0); (0,0,1) \} \) are also in \[ T_2 = \text{span} \{ (1,1,0); (0,0,1); (1,0,1) \}, \] i.e., show explicitly how \( \vec{t}_2 \) in \( T_2 \) corresponds to some given \( \vec{t}_1 \) in \( T_1 \).
Expert Solution
Step 1

Consider the vector space T1=span1,0,0,0,1,0,0,0,1 and T2=span1,1,0,0,0,1,1,0,1

Let t1=a,b,cT1 be an arbitrary vector. Therefore it can be represented as:

                     t1=a,b,c=a1,0,0+b0,1,0+c0,0,1

Let l,m,nT2 be an arbitrary vector. Therefore it can be represented as:

             l,m,n=d1,1,0+e0,0,1+f1,0,1l,m,n=d+f,d,e+f

Solving them for d,e,f, we have:

                       l=d+fm=dn=e+f

Therefore d=m, f=l-m and e=m+n-l

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