Show that (a) if P(A) = P(B) = P(AB), then P(ABUBA) = 0; (b) if P(A) = P(B) = 1, then P(AB) = 1.
Show that (a) if P(A) = P(B) = P(AB), then P(ABUBA) = 0; (b) if P(A) = P(B) = 1, then P(AB) = 1.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![Show that (a) if P(A) = P(B) = P(AB), then P(ABUBA) = 0; (b) if P(A) = P(B) = 1,
then P(AB) = 1.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff6ed396a-58be-4ac0-9d00-206a35697371%2Fea08cccd-d579-4814-9954-93b0634b6600%2Fmanoa6b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Show that (a) if P(A) = P(B) = P(AB), then P(ABUBA) = 0; (b) if P(A) = P(B) = 1,
then P(AB) = 1.
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