Show that 2f E R[a, b] and | [2f(x)] dx = 2 e| f(x) dz. 2.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 50E
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[Integrability: Riemann and Darboux] How do you prove 2? I was told this can be done in a couple lines.

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Let f E R[a, b] (which implies that f is bounded).
1.
For any partition of a, b], show that
U (2f, P) = 2U(f, P), L(2f,P)=2L(f, P).
2.
Show that 2f E R[a, b] and
[2f(x)] dx
f(x) dx.
= 2
a
Transcribed Image Text:Let f E R[a, b] (which implies that f is bounded). 1. For any partition of a, b], show that U (2f, P) = 2U(f, P), L(2f,P)=2L(f, P). 2. Show that 2f E R[a, b] and [2f(x)] dx f(x) dx. = 2 a
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