Show step-by-step calculations. Answer = 1.125 kg A testing sample, initially containing W(0)=4 kg of water, is place in a room of volume V=100 m. Suppose the air humidity h(t) of the room is initially 25% of the saturated air humidity hs, i.e., h(0) =0.25 hg. Given that the temperature of the room remains constant; at saturated air humidity, 1 m³ air contains 0.12 kg of water, i.e., hs =0.12 kg/m³. If 50% of the water in the testing sample is lost after one day, i.e., W(1)=2 kg, determine how much water is left in the testing sample after two days, i.e., W(2). A W(2) = 1.125 Kg F Water contained in a porous material evaporates into the surrounding air. The rate of water evaporation dW(t)/dt is proportional to the water content of the material W(t), and proportional to the difference of the air humidity and the saturated air humidity hs-h(t) of the surrounding air.
Show step-by-step calculations. Answer = 1.125 kg A testing sample, initially containing W(0)=4 kg of water, is place in a room of volume V=100 m. Suppose the air humidity h(t) of the room is initially 25% of the saturated air humidity hs, i.e., h(0) =0.25 hg. Given that the temperature of the room remains constant; at saturated air humidity, 1 m³ air contains 0.12 kg of water, i.e., hs =0.12 kg/m³. If 50% of the water in the testing sample is lost after one day, i.e., W(1)=2 kg, determine how much water is left in the testing sample after two days, i.e., W(2). A W(2) = 1.125 Kg F Water contained in a porous material evaporates into the surrounding air. The rate of water evaporation dW(t)/dt is proportional to the water content of the material W(t), and proportional to the difference of the air humidity and the saturated air humidity hs-h(t) of the surrounding air.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Show step-by-step calculations. Answer = 1.125
kg
A testing sample, initially containing W(0)=4 kg of water, is place in a room of volume V=100
m³. Suppose the air humidity h(t) of the room is initially 25% of the saturated air humidity hs,
i.e., h(0) =0.25 hs. Given that the temperature of the room remains constant; at saturated air
humidity, 1 m air contains 0.12 kg of water, i.e., hs =0.12 kg/m³. If 50% of the water in the
testing sample is lost after one day, i.e., W(1)=2 kg, determine how much water is left in the
testing sample after two days, i.e., W(2).
A W(2) = 1.125 Kg
F Water contained in a porous material evaporates into the surrounding air. The rate of
water evaporation dW(t)/dt is proportional to the water content of the material W(t),
and proportional to the difference of the air humidity and the saturated air humidity
hs-h(t) of the surrounding air.
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