Show me the steps of determine green and information is here step by step
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 13E
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Question
Show me the steps of determine green and information is here step by step
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PII
Joi+šp + feraah ) ( ei+29 + foi+1k`
п-2
foi+6P+ f6i+5h°
fei+19 + föik
i=0
n-2
п-2
f6i+4P+f6i+3h
f6i+6P+f6i+5h
f6i+29+f6i+1k
)(f6i+59+f6i+4k
i=0
i=0
n-2
п-2
«П
f6i+69+f6i+5k+k
(f6i+4P+f6i+3h
f6i+3P+f6i+2h.
f6i9+f6i-1k
J6i+59+f6i44k )+k ||(6i+4P+f6i+3h
J6i+3P+f6i+2h )6i-19+f6i-2k,
i=0
i=0
n-2
foi+6P+ f6i+5h
foi+sp+ foitah ) \ foi+19+ feik
( föi+29 + f6i+1k`
i=0
п-2
п-2
II
f6i+6q+f6i+5k`
f6i+59+f6i+4k .
f6i+6p+f6i+5h
f6i+5P+f6i+4h
i=0
f6i+29+f6i+1k`
f6i+19+f6ik
i=0
п-2
fGi+69+f6i+5k
f6i+59+f6i+4k
п-2
+ k||
f6:9+f6i–1k
f6i-19+fei-2k
i=0
i=0
(foi+29 + f6i+1k`
( foi+6P + foi+5" ) (fet19+ fosk
п-2
II
p
föi+5P + fsi+4h,
i=0
п-2
pg T
f6i+6p+f6i+5h
f6i+5p+f6i+4h
f6i+29+f6i+1k
f6i+19+f6ik
i=0
п-2
п-2
п-2
П
f6i+59+f6i+4k
f6i+69+f6i+5k
f6i+6q+f6i+5k
a|I(76i+59+f6i+4k
f6iq+f6i–1k
+k ||(Foi-19+f6i–2k
i=0
i=0
i=0
п-2
pq]I
fei+6P+f6i+5h
f6i+5P+f6i+4h,
(fei+29+f6i+1k
f6i+19+f6ik
п-2
foi+6P + foi+5h\
(foi+29 + f6i+1k`
i=0
= p]]
foi+5p + f6i+ah ) ( Toi+19 + foik
п-2
f6i+59+f6i+4k
f6i-19+f6i-2k
i=0
q + k ]T(_fiq+fôi–1k
f6i+6q+f6i+5k)
i=0
п-2
foi+6p+f6i+5h
Pg |1( F6i+5P+f6i+ah,
fei+29+f6i+1k
f6i+19+f6ik
п-2
foi+29 + foi+1k
( föi+6P+ föi+5h
PII
\ foi+5P+ foi+ah ) \ foi+19 + foik:
i=0
+
fên-79+fên-8k
fên-69+fen-7k
i=0
q+q
12](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F158aed3a-44ed-4147-bb6c-9729d6a7101b%2Fb5df496c-3b2b-44d9-b8ff-ca2db52fc424%2Fv5ya7v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:476i+3P+f6i+2h6i+69+f6i+5k)PI(76i+5P+f6i+4h ) \ T6i+19+S6ik)
PII
Joi+šp + feraah ) ( ei+29 + foi+1k`
п-2
foi+6P+ f6i+5h°
fei+19 + föik
i=0
n-2
п-2
f6i+4P+f6i+3h
f6i+6P+f6i+5h
f6i+29+f6i+1k
)(f6i+59+f6i+4k
i=0
i=0
n-2
п-2
«П
f6i+69+f6i+5k+k
(f6i+4P+f6i+3h
f6i+3P+f6i+2h.
f6i9+f6i-1k
J6i+59+f6i44k )+k ||(6i+4P+f6i+3h
J6i+3P+f6i+2h )6i-19+f6i-2k,
i=0
i=0
n-2
foi+6P+ f6i+5h
foi+sp+ foitah ) \ foi+19+ feik
( föi+29 + f6i+1k`
i=0
п-2
п-2
II
f6i+6q+f6i+5k`
f6i+59+f6i+4k .
f6i+6p+f6i+5h
f6i+5P+f6i+4h
i=0
f6i+29+f6i+1k`
f6i+19+f6ik
i=0
п-2
fGi+69+f6i+5k
f6i+59+f6i+4k
п-2
+ k||
f6:9+f6i–1k
f6i-19+fei-2k
i=0
i=0
(foi+29 + f6i+1k`
( foi+6P + foi+5" ) (fet19+ fosk
п-2
II
p
föi+5P + fsi+4h,
i=0
п-2
pg T
f6i+6p+f6i+5h
f6i+5p+f6i+4h
f6i+29+f6i+1k
f6i+19+f6ik
i=0
п-2
п-2
п-2
П
f6i+59+f6i+4k
f6i+69+f6i+5k
f6i+6q+f6i+5k
a|I(76i+59+f6i+4k
f6iq+f6i–1k
+k ||(Foi-19+f6i–2k
i=0
i=0
i=0
п-2
pq]I
fei+6P+f6i+5h
f6i+5P+f6i+4h,
(fei+29+f6i+1k
f6i+19+f6ik
п-2
foi+6P + foi+5h\
(foi+29 + f6i+1k`
i=0
= p]]
foi+5p + f6i+ah ) ( Toi+19 + foik
п-2
f6i+59+f6i+4k
f6i-19+f6i-2k
i=0
q + k ]T(_fiq+fôi–1k
f6i+6q+f6i+5k)
i=0
п-2
foi+6p+f6i+5h
Pg |1( F6i+5P+f6i+ah,
fei+29+f6i+1k
f6i+19+f6ik
п-2
foi+29 + foi+1k
( föi+6P+ föi+5h
PII
\ foi+5P+ foi+ah ) \ foi+19 + foik:
i=0
+
fên-79+fên-8k
fên-69+fen-7k
i=0
q+q
12
![Bxn-10n-2
YIn-1 + dxn-4
Xn+1 = axn-2 +
n = 0,1, ...,
(1)
The following special case of Eq.(1) has been studied
Xn-1Xn-2
In+1 = Tn-2 +
(8)
In-1+ Xn-4'
where the initial conditions x-4, x-3, x-2, -1,and xo are arbitrary non zero real
numbers.
Theorem 4. Let {Tn}-4 be a solution of Eq.(8). Then for n = 0, 1, 2,..](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F158aed3a-44ed-4147-bb6c-9729d6a7101b%2Fb5df496c-3b2b-44d9-b8ff-ca2db52fc424%2Fookm05s_processed.png&w=3840&q=75)
Transcribed Image Text:Bxn-10n-2
YIn-1 + dxn-4
Xn+1 = axn-2 +
n = 0,1, ...,
(1)
The following special case of Eq.(1) has been studied
Xn-1Xn-2
In+1 = Tn-2 +
(8)
In-1+ Xn-4'
where the initial conditions x-4, x-3, x-2, -1,and xo are arbitrary non zero real
numbers.
Theorem 4. Let {Tn}-4 be a solution of Eq.(8). Then for n = 0, 1, 2,..
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