Show how the mergesort algorithm executes on the string MATERIAL You should recall from lecture that we can use a graph to visualize the merge sort algorithm. At the very top of the graph, you have one node representing the original input list. At the very bottom, you have one node representing a sorted version of your input list. In the middle, you have nodes and edges representing the steps you take to execute merge sort. For this question, you are to execute the merge sort algorithm and show your work, with the provided string for input. You will consider each character in the input string as an element in an input list to merge sort. For example, the string "HELLO" would mean you input the list ["H", "E", "L", "L", "O"] into the merge sort algorithm.

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Show how the mergesort algorithm executes on the string MATERIAL
You should recall from lecture that we can use a graph to visualize the merge sort algorithm. At the very top of the
graph, you have one node representing the original input list. At the very bottom, you have one node representing a
sorted version of your input list. In the midle, you have nodes and edges representing the steps you take to execute
merge sort.
For this question, you are to execute the merge sort algorithm and show your work, with the provided string for
input. You will consider each character in the input string as an element in an input list to merge sort. For example,
the string "HELLO" would mean you input the list ["H", "E", "L", "L", "O"] into the merge sort algorithm.
Fòr convenience, the pseudocode of the mergesort algorithm is shown below:
MergeSort(array V, int p, int r) {
if (p = r) then // do nothing
else {
// we have at least 2 items
q = (p + r)/2
MergeSort(V, p, q) // sort V[p..a]
MergeSort(V, q+1, r) // sort V[q+1.r]
Merge(V, p, q, r) // merge everything together
Merge(array V, int p, int q, int r) {
// merges V[p..g] with V[q+1.r]
// declare a temporary array S to store
// the sorted sequence
array S[p..r]
i = k = p// initialize pointers
j = q+1
while (i <= q and j <= r) {
// while both subarrays are nonempty
if (V[i] <= V[j]) then
// copy from left subarray
S[k++] = V[i++]
else
// copy from right subarray
S[k++] = V[i++]
%3D
// copy any leftover to S from the left subarray
while (i <= q) do
S[k++] = V[i++]
// copy any leftover to S from the right subarray
while (j <= r) do
S[k++] = V[j++]
// copy S back to V
for i = p to r do V[i) = S[i]
%3D
%3D
Transcribed Image Text:Show how the mergesort algorithm executes on the string MATERIAL You should recall from lecture that we can use a graph to visualize the merge sort algorithm. At the very top of the graph, you have one node representing the original input list. At the very bottom, you have one node representing a sorted version of your input list. In the midle, you have nodes and edges representing the steps you take to execute merge sort. For this question, you are to execute the merge sort algorithm and show your work, with the provided string for input. You will consider each character in the input string as an element in an input list to merge sort. For example, the string "HELLO" would mean you input the list ["H", "E", "L", "L", "O"] into the merge sort algorithm. Fòr convenience, the pseudocode of the mergesort algorithm is shown below: MergeSort(array V, int p, int r) { if (p = r) then // do nothing else { // we have at least 2 items q = (p + r)/2 MergeSort(V, p, q) // sort V[p..a] MergeSort(V, q+1, r) // sort V[q+1.r] Merge(V, p, q, r) // merge everything together Merge(array V, int p, int q, int r) { // merges V[p..g] with V[q+1.r] // declare a temporary array S to store // the sorted sequence array S[p..r] i = k = p// initialize pointers j = q+1 while (i <= q and j <= r) { // while both subarrays are nonempty if (V[i] <= V[j]) then // copy from left subarray S[k++] = V[i++] else // copy from right subarray S[k++] = V[i++] %3D // copy any leftover to S from the left subarray while (i <= q) do S[k++] = V[i++] // copy any leftover to S from the right subarray while (j <= r) do S[k++] = V[j++] // copy S back to V for i = p to r do V[i) = S[i] %3D %3D
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