Show diagram in using the 3D vector simulator: https://mathinsight.org/vectors_cartesian_coordinates_2d_3d   the vector is at angle 36.04degDepression   please use the vector in link for resultant vector using the interactive JUST JPG/screenshot the 3d vector

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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 Show diagram in using the 3D vector simulator:

https://mathinsight.org/vectors_cartesian_coordinates_2d_3d

 

the vector is at angle 36.04degDepression

 

please use the vector in link for resultant vector using the interactive JUST JPG/screenshot the 3d vector 

The component is the xy plane is:
|Fy|=/F,? + F,²
2
ху
X
=V402 + 10²
=V1600 + 100
=41. 23N
The z-component is:
|F:| = -30
Let the angle between the xy-component and the
resultant vector be 0 (this is like a right angled
traingle with sides: |Fxy|, |F2| and |F|
Thus,
tan 0=-
|Fxy|
-30
41.23
=-0.7276
0=tan- (-0.7276)
=-36. 04°
Thus the vector is at angle
of 36.04degDepression from the z-plane
Transcribed Image Text:The component is the xy plane is: |Fy|=/F,? + F,² 2 ху X =V402 + 10² =V1600 + 100 =41. 23N The z-component is: |F:| = -30 Let the angle between the xy-component and the resultant vector be 0 (this is like a right angled traingle with sides: |Fxy|, |F2| and |F| Thus, tan 0=- |Fxy| -30 41.23 =-0.7276 0=tan- (-0.7276) =-36. 04° Thus the vector is at angle of 36.04degDepression from the z-plane
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