Show development for the solution If the confidence level is 95%, find the critical t value for n = 15 (using the z distribution table). a) for one tail and b) two tails
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Show development for the solution
If the confidence level is 95%, find the critical t value for n = 15 (using the z distribution table).
a) for one tail and
b) two tails
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- Determine 95% prediction limits for prediction limits for the price, Y, when the quality is when X = 63.7 and 95% confidence limits for b (the slope of the least squares line).Use the t-distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distributions are relatively normal. Test Ho : HA = Ha VS H. : HA # Hg using the fact that Group A has 8 cases with a mean of 125 and a standard deviation of 18 while Group B has 15 cases with a mean of 118 and a standard deviation of 14. (a) Give the test statistic and thep-value. Round your answer for the test statistic to two decimal places and your answer for the p- value to three decimal places. test statistic = p-value = eTextbook and Media (b) What is the conclusion of the test? Test at a 10% level. O Reject Ho. O Do not reject Ho. eTextbook and MediaUse the t-distribution to find a confidence interval for a difference in means y, - M, given the relevant sample results. Give the best estimate for 41 - M2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 99% confidence interval for My - A using the sample results x1 = 546, S, = 117, m, = 340 and X2 = 451,52 = 90, M2 = 200 Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places. Best estimate = Margin of error = Confidence interval
- weight is recorded in grams. Linda feeds her rats Formula A, Tuan feeds his rats Formula B, and Javier feeds his rats Formula C. At the end of a specified time period, each rat is weighed again, and the net gain in grams is recorded. Using a significance level of 0.05, test the hypothesis that the three formulas produce the same mean weight gain.H0: μ1 = μ2 = μ3Ha: At least two of the means differ from each other Forumla A Forumla B Forumla C 51 39.4 53.6 55.8 55.1 42.4 53.8 33.1 50.1 43.2 58.7 40.4 42.1 40.4 46.9 50.1 19 45.6 59.5 43.2 48.7 35.4 32.2 49.5 45.2 16.4 56.1 Run a one-factor ANOVA with α=0.05. Report the F-ratio to 4 decimal places and the p-value to 4 decimal places.F = p-value = Based on the p-value, what is the conclusion Reject the null hypothesis: at least one of the group means is different Fail to reject the null hypothesis: not sufficient evidence to suggest the group means are differentAssume that we want to construct a confidence interval. Which letter is correct? The confidence level is 99%, σ=3624 thousand dollars, and the histogram of 60 player salaries (in thousands of dollars) of footbal players on a team is as shown. a) find the critical value tα/2 b) find the critical value zα/2 c) neither the normal distribution nor the t distribution applies.For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x = 6.4, y = 5.9, r= - 0.319, P-value = 0.024, and y = 8.29 – 0.379x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x = 8. Use a 0.10 significance level. ..... The best predicted value of y when x= 8 is (Round to one decimal place as needed.)
- The Student's t distribution table gives critical values for the Student's t distribution. Use an appropriate d.f. as the row header. For a right-tailed test, the column header is the value of α found in the one-tail area row. For a left-tailed test, the column header is the value of α found in the one-tail area row, but you must change the sign of the critical value t to −t. For a two-tailed test, the column header is the value of α from the two-tail area row. The critical values are the ±t values shown. A random sample of 46 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.11 years, with sample standard deviation s = 0.77 years. However, it is thought that the overall population mean age of coyotes is μ = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use α = 0.01. Solve the problem using the critical region method of testing (i.e., traditional method). (Round…For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (X) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x=6.2, y = 5.9, r= -0.244, P-value = 0.087, and y =7.68 - 0.285x, Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x= 4. Use a 0.05 significance level. The best predicted value of y when x = 4 is (Round to one decimal place as needed.)For 50 randomly selected speed dates, attractiveness ratings by males of their female date partnerS (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield *= 6.3, y = 6.1. r= - 0.283, P.value = 0.046, and g = 8.39 - 0.369x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x= 4. Use a 0.01 significance level. see score The best predicted value of g when x= 4 is 7. (Round to one decimal place as needed.)
- For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x = 6.4, y = 6.0, r=-0.233, P-value = 0.104, and ŷ= 7.88 -0.292x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x = 4. Use a 0.01 significance level. The best predicted value of y when x = 4 is (Round to one decimal place as needed.)The pulse rates of 176 randomly selected adult males vary from a low of 40 bpm to a high of 116 bpm. Find the minimum sample size required to estimate the mean pulse rate of adult males. Assume that we want 95% confidence that the sample mean is within 2 bpm of the population mean. Assume that o= 10.1 bpm, based on the value s = 10.1 bpm from the sample of 176 male pulse ratesFor 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x=6.4, y= 6.0, r= -0.124, P-value = 0.391, and y = 6.95-0.146x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x = 7. Use a 0.10 significance level. The best predicted value of y when x 7 is. (Round to one decimal place as needed.)