Show a detailed solution in solving for the sum of the square of variance of the distance measurements given. Determine an error using 99.9% probability Note: x is the second digit in your SLMIS number. Trials Measurement, m Frequency 35.4 2 2 33.3 2 3 34.1 2 4 36.1 2 34.1 2 33.1 2 7 36.8 33.0 2 9 34.1 2 10 33.7 2
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- The Ahmadi Corporation wants to increase the productivity of its line workers. Four different programs have been suggested to help increase productivity. Twenty employees, making up a sample, have been randomly assigned to one of the four programs and their output for a day's work has been recorded. You are given the results below. At 95% confidence, conduct the ANOVA test to determine whether there is a significant difference in the mean output under the four programs. Program A Program B Program C Program D 150 150 185 175 130 120 120 135 180 160 145 110 Part of the ANOVA table is shown below. Source of Variation Sum of Squares 8,750 Between Groups Within Groups 16,350 Total 220 190 180 175 d.f. 19 150 120 130 175 Mean SquareRefer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.10 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). Click the icon to view the data In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. H9: Ha =0 H1: Ha 0Does Hypnotism Relieve Pain? The table shows the pain levels of patients before and after hypnotism. Pain level is measured on a cm scale. Assume that the two samples are randomly selected. At the 0.05 significance level, test the claim that the mean difference has increased after hypnotism.(Be sure to subtract in the same direction).
- In the 1992 presidential election, Alaska's 40 election districts averaged 2038 votes per district for President Clinton. The standard deviation was 576. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 2038 a population mean or a sample mean? Select an answer Population Mean Sample Mean c. Find the probability that a randomly selected district had fewer than 1842 votes for President Clinton. d. Find the probability that a randomly selected district had between 1997 and 2099 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.Calculate the standard deviation of the data shown. Use technology x 27.6 2.6 13.2 8.3 8.9 3.3 Round to 2 placesA particular fruit's weights are normally distributed, with a mean of 334 grams and a standard deviation of 6 grams. The heaviest 11% of fruits weigh more than how many grams? Give your answer to the nearest gram. Check Answer
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