In an amplifier that has a power gain of 6 dB, what is the voltage gain in dB?
Power Amplifier
The power amplifier is an electronic amplifier designed to maximize the signal strength of a given input. The input signal strength is enhanced to a high enough level to drive output devices such as speakers, headphones, RF (Radio frequency) transmitters, etc. Unlike voltage / current amplifiers, the power amplifier is designed to drive core loads directly and is used as a storage block in the amplifier series.
Maximum Efficiency Criterion
In every field of engineering, there is a tremendous use of the machine and all those machines are equipped for their popular work efficiency so it very much important for operation engineers to monitor the efficiency of the machine, planning engineers to check out the efficiency of the machine before installing the machine and design engineers to design machine for higher efficiency than and then the utility will procure their products that will ultimately lead to profit and loss of the company. It indicates the importance of efficiency right from the initial stage as manufacturing units, intermediate stage as planning coordinators, and end-users stage as a utility.
![---
**Question:**
1. In an amplifier that has a power gain of 6 dB, what is the voltage gain in dB?
---
**Explanation:**
In the text shown, the question involves a basic relationship between power gain and voltage gain in an amplifier, often calculated using decibels (dB). The document requires determining the voltage gain given a power gain of 6 dB.
**Calculation:**
Power gain in decibels (dB) is given by the formula:
\[ \text{Power Gain (dB)} = 10 \cdot \log_{10}\left(\frac{P_{\text{out}}}{P_{\text{in}}}\right) \]
Voltage gain in decibels (dB) is given by:
\[ \text{Voltage Gain (dB)} = 20 \cdot \log_{10}\left(\frac{V_{\text{out}}}{V_{\text{in}}}\right) \]
If the power gain is 6 dB, and assuming the input and output impedances are the same, the voltage gain can be calculated using the following relationship since:
\[ \text{Voltage Gain (dB)} = \text{Power Gain (dB)} / 2 \]
Thus, voltage gain = \( \frac{6}{2} = 3 \) dB.
This information would help students or individuals understand basic calculations and relationships involving decibels in amplifiers.
---
There are no graphs or diagrams in the image, aside from a symbol that resembles a ground symbol often used in electrical diagrams.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d0965ec-e02e-4363-aba0-fca3ccf5b9fe%2Fdcceaae0-2cec-4a62-ad5e-e8993b209060%2Fjm88wz9_processed.jpeg&w=3840&q=75)
According to the question, we need to calculate voltage gain in dB if power gain is 6dB.
Step by step
Solved in 3 steps with 2 images
