Short questions, all-or-nothing. There may be more than one answer per question. axial 3- CN NC Ni CN NC CN equatorial For the square base pyramidal complex [Ni(CN)s]³ shown above, of Cav point group, consider the rotation axes: 2C4 and C2. If the axial CN ligand was substituted by CO, forming [Ni(CO)(CN).]?, maintaining the square pyramidal geometry, which symmetry elements would а. be retained: i. Both C4 and C2. ii. Only the C2. iii. Only the C4. iv. None of the above b. Looking at the symmetry planes: 20v, 20a; Wwhat symmetry elements would be retained if the Co substitution would occur on an equatorial CN ligand (forming again [Ni(CO)(CN).]?) instead? The dihedral planes in this case is the mirror plane that bisects the square planar bonds. i. All gv 2.
Short questions, all-or-nothing. There may be more than one answer per question. axial 3- CN NC Ni CN NC CN equatorial For the square base pyramidal complex [Ni(CN)s]³ shown above, of Cav point group, consider the rotation axes: 2C4 and C2. If the axial CN ligand was substituted by CO, forming [Ni(CO)(CN).]?, maintaining the square pyramidal geometry, which symmetry elements would а. be retained: i. Both C4 and C2. ii. Only the C2. iii. Only the C4. iv. None of the above b. Looking at the symmetry planes: 20v, 20a; Wwhat symmetry elements would be retained if the Co substitution would occur on an equatorial CN ligand (forming again [Ni(CO)(CN).]?) instead? The dihedral planes in this case is the mirror plane that bisects the square planar bonds. i. All gv 2.
Chemistry
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ISBN:9781305957404
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![## Symmetry in Square Base Pyramidal Complexes
### Question 2
Short questions, all-or-nothing. There may be more than one answer per question.
#### Diagram Description:
The diagram shows a square base pyramidal complex with a nickel center (Ni) coordinated to five cyanide (CN) ligands, labeled as [Ni(CN)5]3-. It features one axial CN ligand and four equatorial CN ligands arranged in a square planar geometry. The terms "axial" and "equatorial" are marked to indicate the positions of the ligands.
### Part a
For the square base pyramidal complex \([Ni(CN)_5]^{3-}\) shown above, belonging to the \(C_{4v}\) point group, consider the rotation axes: \(2C_4\) and \(C_2\). If the axial CN ligand was substituted by CO, forming \([Ni(CO)(CN)_4]^{2-}\), maintaining the square pyramidal geometry, which symmetry elements would be retained:
i. Both \(C_4\) and \(C_2\).
ii. Only the \(C_2\).
iii. Only the \(C_4\).
iv. None of the above
### Part b
Looking at the symmetry planes: \(2σ_v\), \(2σ_d\); what symmetry elements would be retained if the CO substitution would occur on an equatorial CN ligand (forming again \([Ni(CO)(CN)_4]^{2-}\) instead)? The dihedral planes in this case are the mirror planes that bisect the square planar bonds.
i. All \(σ_v\)
ii. All \(σ_d\)
iii. At least 1 \(σ_d\)
iv. At least 1 \(σ_v\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c04facf-07ed-4ba0-b632-2bed7ceb7fbe%2Ffb1f938a-b300-46b5-a435-2802290983fa%2F0v0hfke_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Symmetry in Square Base Pyramidal Complexes
### Question 2
Short questions, all-or-nothing. There may be more than one answer per question.
#### Diagram Description:
The diagram shows a square base pyramidal complex with a nickel center (Ni) coordinated to five cyanide (CN) ligands, labeled as [Ni(CN)5]3-. It features one axial CN ligand and four equatorial CN ligands arranged in a square planar geometry. The terms "axial" and "equatorial" are marked to indicate the positions of the ligands.
### Part a
For the square base pyramidal complex \([Ni(CN)_5]^{3-}\) shown above, belonging to the \(C_{4v}\) point group, consider the rotation axes: \(2C_4\) and \(C_2\). If the axial CN ligand was substituted by CO, forming \([Ni(CO)(CN)_4]^{2-}\), maintaining the square pyramidal geometry, which symmetry elements would be retained:
i. Both \(C_4\) and \(C_2\).
ii. Only the \(C_2\).
iii. Only the \(C_4\).
iv. None of the above
### Part b
Looking at the symmetry planes: \(2σ_v\), \(2σ_d\); what symmetry elements would be retained if the CO substitution would occur on an equatorial CN ligand (forming again \([Ni(CO)(CN)_4]^{2-}\) instead)? The dihedral planes in this case are the mirror planes that bisect the square planar bonds.
i. All \(σ_v\)
ii. All \(σ_d\)
iii. At least 1 \(σ_d\)
iv. At least 1 \(σ_v\)
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