Short questions, all-or-nothing. There may be more than one answer per question. axial 3- CN NC Ni CN NC CN equatorial For the square base pyramidal complex [Ni(CN)s]³ shown above, of Cav point group, consider the rotation axes: 2C4 and C2. If the axial CN ligand was substituted by CO, forming [Ni(CO)(CN).]?, maintaining the square pyramidal geometry, which symmetry elements would а. be retained: i. Both C4 and C2. ii. Only the C2. iii. Only the C4. iv. None of the above b. Looking at the symmetry planes: 20v, 20a; Wwhat symmetry elements would be retained if the Co substitution would occur on an equatorial CN ligand (forming again [Ni(CO)(CN).]?) instead? The dihedral planes in this case is the mirror plane that bisects the square planar bonds. i. All gv 2.

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## Symmetry in Square Base Pyramidal Complexes

### Question 2

Short questions, all-or-nothing. There may be more than one answer per question.

#### Diagram Description:
The diagram shows a square base pyramidal complex with a nickel center (Ni) coordinated to five cyanide (CN) ligands, labeled as [Ni(CN)5]3-. It features one axial CN ligand and four equatorial CN ligands arranged in a square planar geometry. The terms "axial" and "equatorial" are marked to indicate the positions of the ligands.

### Part a

For the square base pyramidal complex \([Ni(CN)_5]^{3-}\) shown above, belonging to the \(C_{4v}\) point group, consider the rotation axes: \(2C_4\) and \(C_2\). If the axial CN ligand was substituted by CO, forming \([Ni(CO)(CN)_4]^{2-}\), maintaining the square pyramidal geometry, which symmetry elements would be retained:

i. Both \(C_4\) and \(C_2\).

ii. Only the \(C_2\).

iii. Only the \(C_4\).

iv. None of the above

### Part b

Looking at the symmetry planes: \(2σ_v\), \(2σ_d\); what symmetry elements would be retained if the CO substitution would occur on an equatorial CN ligand (forming again \([Ni(CO)(CN)_4]^{2-}\) instead)? The dihedral planes in this case are the mirror planes that bisect the square planar bonds.

i. All \(σ_v\)

ii. All \(σ_d\)

iii. At least 1 \(σ_d\)

iv. At least 1 \(σ_v\)
Transcribed Image Text:## Symmetry in Square Base Pyramidal Complexes ### Question 2 Short questions, all-or-nothing. There may be more than one answer per question. #### Diagram Description: The diagram shows a square base pyramidal complex with a nickel center (Ni) coordinated to five cyanide (CN) ligands, labeled as [Ni(CN)5]3-. It features one axial CN ligand and four equatorial CN ligands arranged in a square planar geometry. The terms "axial" and "equatorial" are marked to indicate the positions of the ligands. ### Part a For the square base pyramidal complex \([Ni(CN)_5]^{3-}\) shown above, belonging to the \(C_{4v}\) point group, consider the rotation axes: \(2C_4\) and \(C_2\). If the axial CN ligand was substituted by CO, forming \([Ni(CO)(CN)_4]^{2-}\), maintaining the square pyramidal geometry, which symmetry elements would be retained: i. Both \(C_4\) and \(C_2\). ii. Only the \(C_2\). iii. Only the \(C_4\). iv. None of the above ### Part b Looking at the symmetry planes: \(2σ_v\), \(2σ_d\); what symmetry elements would be retained if the CO substitution would occur on an equatorial CN ligand (forming again \([Ni(CO)(CN)_4]^{2-}\) instead)? The dihedral planes in this case are the mirror planes that bisect the square planar bonds. i. All \(σ_v\) ii. All \(σ_d\) iii. At least 1 \(σ_d\) iv. At least 1 \(σ_v\)
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