shifted right 3 units and shifted down 4 units. O f(z) = Va + 3 - 4 O f(z) = VI -3- 4 O f(z) = Vz + 3 + 4 O f(z) = VI – 3 + 4 The graph of f(x) stretched vertically by a factor of 5. O f(z) = 5/T O f(2) = VE %3D O f(z) = V5x O f(x) =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Transformations of Functions

This content is intended for educational purposes to help students understand the transformations of functions, specifically the square root function \( f(x) = \sqrt{x} \).

#### Horizontal and Vertical Shifting

**Original Function:**
\[ f(x) = \sqrt{x} \]

**Transformed Functions:**
1. **Shift Right 3 Units and Down 4 Units:**
    - To shift the graph of \( f(x) = \sqrt{x} \) right by 3 units, replace \( x \) with \( x-3 \).
    - To shift it down by 4 units, subtract 4 from the entire function.
    - This results in the transformed function: 
      \[ f(x) = \sqrt{x - 3} - 4 \]

    **Multiple Choice Answers (one correct):**
    - \( \circ f(x) = \sqrt{x + 3} - 4 \)
    - \( \circ f(x) = \sqrt{x - 3} - 4 \)   ⬅️ Correct Answer
    - \( \circ f(x) = \sqrt{x + 3} + 4 \)
    - \( \circ f(x) = \sqrt{x - 3} + 4 \)

#### Vertical Stretching or Shrinking

**Original Function:**
\[ f(x) = \sqrt{x} \]

**Transformed Functions:**
2. **Stretch Vertically by a Factor of 5:**
    - To stretch the graph of \( f(x) = \sqrt{x} \) vertically by a factor of 5, multiply the entire function by 5.
    - This results in the transformed function:
      \[ f(x) = 5\sqrt{x} \]

    **Multiple Choice Answers (one correct):**
    - \( \circ f(x) = 5\sqrt{x} \)  ⬅️ Correct Answer
    - \( \circ f(x) = \frac{1}{5}\sqrt{x} \)
    - \( \circ f(x) = \sqrt{5x} \)
    - \( \circ f(x) = \sqrt{\frac{1}{5}}x \)

#### Summary
In this lesson, you learned how to apply horizontal and vertical shifts to the square root function, as well as how to perform vertical stretching. Transformations such as these
Transcribed Image Text:### Transformations of Functions This content is intended for educational purposes to help students understand the transformations of functions, specifically the square root function \( f(x) = \sqrt{x} \). #### Horizontal and Vertical Shifting **Original Function:** \[ f(x) = \sqrt{x} \] **Transformed Functions:** 1. **Shift Right 3 Units and Down 4 Units:** - To shift the graph of \( f(x) = \sqrt{x} \) right by 3 units, replace \( x \) with \( x-3 \). - To shift it down by 4 units, subtract 4 from the entire function. - This results in the transformed function: \[ f(x) = \sqrt{x - 3} - 4 \] **Multiple Choice Answers (one correct):** - \( \circ f(x) = \sqrt{x + 3} - 4 \) - \( \circ f(x) = \sqrt{x - 3} - 4 \) ⬅️ Correct Answer - \( \circ f(x) = \sqrt{x + 3} + 4 \) - \( \circ f(x) = \sqrt{x - 3} + 4 \) #### Vertical Stretching or Shrinking **Original Function:** \[ f(x) = \sqrt{x} \] **Transformed Functions:** 2. **Stretch Vertically by a Factor of 5:** - To stretch the graph of \( f(x) = \sqrt{x} \) vertically by a factor of 5, multiply the entire function by 5. - This results in the transformed function: \[ f(x) = 5\sqrt{x} \] **Multiple Choice Answers (one correct):** - \( \circ f(x) = 5\sqrt{x} \) ⬅️ Correct Answer - \( \circ f(x) = \frac{1}{5}\sqrt{x} \) - \( \circ f(x) = \sqrt{5x} \) - \( \circ f(x) = \sqrt{\frac{1}{5}}x \) #### Summary In this lesson, you learned how to apply horizontal and vertical shifts to the square root function, as well as how to perform vertical stretching. Transformations such as these
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