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Shahlina Active Now IATH 1101- Differential Calculus MAXIMA AND MINIMA I- Determine the Maxima and Minima and the Point of inflecti 1. y = x* – 6x3 2. y = x + x2 – x3 3. у%3D 2х3 - 3х2 -12х + 12 4. y = 2x3 – 11x2 + 12x + 10 5. y = 2(3x + 20)2 – 3x* 6. y = x3 + 9(a – x)3 where a is constant | 2x 7. у %3D x2+1 Il- Plot the following 1. у%3 (x — 1)(х - 2)(х — 3) 2. y = x3 – 6x2 - 8. + V

Shahlina Active Now IATH 1101- Differential Calculus MAXIMA AND MINIMA I- Determine the Maxima and Minima and the Point of inflecti 1. y = x* – 6x3 2. y = x + x2 – x3 3. у%3D 2х3 - 3х2 -12х + 12 4. y = 2x3 – 11x2 + 12x + 10 5. y = 2(3x + 20)2 – 3x* 6. y = x3 + 9(a – x)3 where a is constant | 2x 7. у %3D x2+1 Il- Plot the following 1. у%3 (x — 1)(х - 2)(х — 3) 2. y = x3 – 6x2 - 8. + V

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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8 Shahlina Active Now. ATH 1101- Differential Calculus MAXIMA AND MINIMA I- Determine the Maxima and Minima and the Point of inflecti 1. y = x* – 6x3 2. у%3Dх +x2 — х3 3. у%3D 2х3 — Зx2-12х + 12 4. y = 2x3 – 11x2 + 12x + 10 5. y = 2(3x + 20)2 – 3x4 6. y = x3 + 9(a – x)³ where a is constant 2x 7. y = x²+1 l- Plot the following 1. у%3 (х—1)(х — 2)(х — 3) 2. y = x3 – 6x2 More Edit
Transcribed Image Text:8 Shahlina Active Now. ATH 1101- Differential Calculus MAXIMA AND MINIMA I- Determine the Maxima and Minima and the Point of inflecti 1. y = x* – 6x3 2. у%3Dх +x2 — х3 3. у%3D 2х3 — Зx2-12х + 12 4. y = 2x3 – 11x2 + 12x + 10 5. y = 2(3x + 20)2 – 3x4 6. y = x3 + 9(a – x)³ where a is constant 2x 7. y = x²+1 l- Plot the following 1. у%3 (х—1)(х — 2)(х — 3) 2. y = x3 – 6x2 More Edit
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