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Set up a double integral that gives the area of the surface of the graph region R. ƒ (x, y) = xª – 5xy − 9y R={(x,y):-5≤ x ≤5,- 4y <4} L₁1²₁1+(4x²-53) - (45) ° - 5x)ª dy dx Lºslª √¹ + (4x³ - 5y) - (45yª – 5x)” dy dx O lªl², v1 + (4x³− 5y)² = (45yª – 5x)ª dy dx L²lª² √¹ - (4x³-5y)² + (45y¹ − 5x)² dx dy O [²3 [², √ ¹ + (4x³ + 5y)² - (45yª + 5x)²³ dy dx

Set up a double integral that gives the area of the surface of the graph region R. ƒ (x, y) = xª – 5xy − 9y R={(x,y):-5≤ x ≤5,- 4y <4} L₁1²₁1+(4x²-53) - (45) ° - 5x)ª dy dx Lºslª √¹ + (4x³ - 5y) - (45yª – 5x)” dy dx O lªl², v1 + (4x³− 5y)² = (45yª – 5x)ª dy dx L²lª² √¹ - (4x³-5y)² + (45y¹ − 5x)² dx dy O [²3 [², √ ¹ + (4x³ + 5y)² - (45yª + 5x)²³ dy dx

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Set up a double integral that gives the area of the surface of the graph of f over the region R ƒ(x, y) = x² – 5xy – 9v³ R=(x,y):-5≤ x ≤5. - 44 y ≤4} P₁²₁ 1+(4x²-59) - (+53 - 5x)" dy dx ° Lºsl′a √1-(tx² - 5y³)² – (453ª − 5x) dyd'x °1′41'²s1 - (4x²-59)²-(459²-5a)ª dy dz ₁1-(4x³-5y)²-(4514-5x) dx dy ° ſºslª, √]1 - (4x ² - 5y)ª − (45yª + 5x) dydx
Transcribed Image Text:Set up a double integral that gives the area of the surface of the graph of f over the region R ƒ(x, y) = x² – 5xy – 9v³ R=(x,y):-5≤ x ≤5. - 44 y ≤4} P₁²₁ 1+(4x²-59) - (+53 - 5x)" dy dx ° Lºsl′a √1-(tx² - 5y³)² – (453ª − 5x) dyd'x °1′41'²s1 - (4x²-59)²-(459²-5a)ª dy dz ₁1-(4x³-5y)²-(4514-5x) dx dy ° ſºslª, √]1 - (4x ² - 5y)ª − (45yª + 5x) dydx
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