Set hasDigit to true if the 3-character passCode contains a digit.345154.2174782.qx3zqy78string passCode;9.hasDigit = false;cin >> passCode;10111213if (hasDigit) {cout << "Has a digit." << endl;}else {cout << "Has no digit." << endl;1415161718192021return 0;22 }RunCommon student error

Here I have taken input from the user for the passcode. Next, I have used a for loop to iterate over…

Answered: Set hasDigit to true if the 3-character…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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String with digit. Using C++ Set hasDigit to true if the 3-character passCode contains a digit. #include <iostream>#include <string>#include <cctype>using namespace std; int main() { bool hasDigit; string passCode; hasDigit = false; cin >> passCode; hasDigit = true; if (hasDigit) { cout << "Has a digit." << endl; } else { cout << "Has no digit." << endl; } return 0;}
Create pseudocode for the following #include <iostream> #include <string> #include <cstdlib> #include <ctime> using namespace std; char water[10][10] = {{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'},{'~','~','~','~','~','~','~','~','~','~'}}; void createBoard(int &numShip); void promptCoords(int& userX, int &userY); void shipGen(int shipX[] ,int shipY[], int &numShip); void testCoords(int &userX, int &userY, int shipX[], int shipY[], int &numShip, int& victory); void updateBoard();
Coorect the Following C++ code: #include <bits/stdc++.h>#include <iostream>#include <fstream>#include <string>#include <cctype> using namespace std; // Function to print available currencies for exchangevoid printCurrencies() { cout << "Available currencies for exchange: " << endl; cout << "SAR --> Saudi Arabia Riyal" << endl; cout << "KWD --> Kuwaiti Dinar" << endl; cout << "QAR --> Qatar Riyal" << endl; cout << "AED --> United Arab Emirates Dirham" << endl; cout << "BHD --> Bahraini Dinar" << endl; cout << "OMR --> Omani Rial" << endl;} // Function to convert currencydouble convertCurrency(string fromCurrency, string toCurrency, double amount) { ifstream exchangeRateFile("ExchangeRate.txt"); // Open file for reading string line; double desiredRate=0; while (getline(exchangeRateFile, line)) { // Read file…
Please modify the following code using getline(cin,strObj) with cout<<strObj<<endl; or getline(infile,strObj) with outfile<<strObj<<endl; #include <iostream>#include <fstream>#include <cstdlib> #include <string> int main(){string fileOne = "info.txt"; // put the filename up frontstring fileTwo = "info.bak";char ch;ifstream inFile;ofstream outfile;try //this block tries to open the input file{// open a basic input streaminFile.open(fileOne.c_str());if (inFile.fail()) throw fileOne;} // end of outer try blockcatch (string in) // catch for outer try block{cout << "The input file " << in<< " was not successfully opened." << endl<< " No backup was made." << endl;exit(1);}try // this block tries to open the output file and{ // perform all file processingoutfile.open(fileTwo.c_str());if (outfile.fail())throw fileTwo;while ((ch = inFile.get())!= EOF)outfile.put(ch);inFile.close();outfile.close();}catch…
Code is in C++ Instructions Write a program that reads in a line consisting of a student’s name, Social Security number, user ID, and password. The program outputs the string in which all the digits of the Social Security number and all the characters in the password are replaced by x. (The Social Security number is in the form 000-00-0000, and the user ID and the password do not contain any spaces.) Your program should not use the operator [] to access a string element. Input is as follows highlighted in bold John Doe 333224444 DoeJ 123Password My problem is with my output, i am close with the code, but i have attached what happens on my output and i cannot figure out why? You can see how it prints out multiple times but i am lost? The terminal image is also attached. Thank you! Here is the code: #include <iostream> //include statement(s)#include <iomanip>#include <string> using namespace std; //using namespace statement(s) void getInfo(string info); //void…
please use DEQUE #include <iostream>#include <string>#include <deque> using namespace std; const int AIRPORT_COUNT = 12;string airports[AIRPORT_COUNT] = {"DAL","ABQ","DEN","MSY","HOU","SAT","CRP","MID","OKC","OMA","MDW","TUL"}; int main(){// define stack (or queue ) herestring origin;string dest;string citypair;cout << "Loading the CONTAINER ..." << endl;// LOAD THE STACK ( or queue) HERE// Create all the possible Airport combinations that could exist from the list provided.// i.e DALABQ, DALDEN, ...., ABQDAL, ABQDEN ...// DO NOT Load SameSame - DALDAL, ABQABQ, etc .. cout << "Getting data from the CONTAINER ..." << endl;// Retrieve data from the STACK/QUEUE here } Using the attached shell program (AirportCombos.cpp), create a list of strings to process and place on a STL DEQUE container. Using the provided 3 char airport codes, create a 6 character string that is the origin & destination city pair. Create all the possible…
// NewMultiply.cpp - This program prints the numbers 0 through 10 along // with these values multiplied by 2 and by 10. // Input: None // Output: Prints the numbers 0 through 10 along with their values multiplied by 2 and by 10. #include <iostream> #include <string> using namespace std; int main() { string head1 = "Number: "; string head2 = "Multiplied by 2: "; string head3 = "Multiplied by 10: "; int numberCounter; // Numbers 0 through 10 int byTen; // Stores the number multiplied by 10 int byTwo; // Stores the number multiplied by 2 const int NUM_LOOPS = 10; // Constant used to control loop // This is the work done in the housekeeping() function cout << "0 through 10 multiplied by 2 and by 10." << endl; // This is the work done in the detailLoop() function // Write your for loop here. // This is the work done in the endOfJob() function return 0; } // End of main()
It wont display the order total // JumpinJava.cpp - This program looks up and prints the names and prices of coffee orders. // Input: Interactive // Output: Name and price of coffee orders or error message if add-in is not found #include <iostream> #include <string> using namespace std; int main() { // Declare variables. string addIn; // Add-in ordered const int NUM_ITEMS = 5; // Named constant // Initialized array of add-ins string addIns[] = {"Cream", "Cinnamon", "Chocolate", "Amaretto", "Whiskey"}; // Initialized array of add-in prices double addInPrices[] = {.89, .25, .59, 1.50, 1.75}; bool foundIt = false; // Flag variable int x; // Loop control variable double orderTotal = 2.00; // All orders start with a 2.00 charge // Get user input cout << "Enter coffee add-in or XXX to quit: "; cin >> addIn; // Write the rest of the program here. while(addIn != "XXX") //loop until user…
11 // Identify the incorrect code by line number (i.e. 1, 6, 18). Enter one line number in each answer box. // This code snippet is from a program that inputs chararacters from B....... // UART RX1, echos back chars+1. 1.#include "pic24_all.h" 2.#include "std_io.h" 3.int main(void) { 4. uint8_t u8_c; 5. 6. configClock(); 7. configDefaultUART(DEFAULT_BAUDRATE); 8. 9. printf("\nHello World!\n"); 10. 11. // Echo character + 1; 12. while (1) { 13. u8 c = inChar(); //get character 14. outChar(u8_c); 15. 18 ctt: //echo the character //increment the character
8. Select the value of x, y so that the following code outputs: containedCircle c = { {10, 15}, 3};Point2D p = {x, y};if(c.contains(p)){std::cout << "contained" << std::endl;}A. x=7, y=18B. x=10, y=20C. x=11, y=14D. None of the above.
C++ reverse string allow the user to enter a string, display the results short code

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Set hasDigit to true if the 3-character passCode contains a digit. 345154.2174782.qx3zqy7 8. string passCode; 9. 10 hasDigit = false; cin >> passCode; 11 12 13 if (hasDigit) { cout << "Has a digit." < endl; } else { cout << "Has no digit." < endl; 14 15 16 17 18 19 20 21 return 0; 22 }