Set 25 Name: GEECKEY C. ROJO The following information is given in connection with test performed on a 120 Kva 8600/240 volt 70 cycle transformer: Open circuit test..... 240 volts; Poc=295 watts Short circuit test.... 185 volts; Psc= 655 watts; Isc 13.95349 amps 1. Calculate the percent efficiency when the transformer is delivering rated kva at a power factor of 8591 Answer: 44.5% 2. Calculate the percent efficiency when the load is 125 Kva at a power factor of .8764 Answer: 94.20% 3. Calculate the percent efficiency when the load is 77.5519 Kw at a power factor of .6863 Answer: 26.58%

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Set 25
GEECKEY C. Rajo
The following information is given in connection with test performed on a
120 Kva 8600/240 volt 70 cycle transformer:
Name:
Open circuit test..... 240 volts; Poc=295 watts
Short circuit test.... 185 volts; Psc= 655 watts; Isc 13.95349 amps
1. Calculate the percent efficiency when the transformer is delivering rated kva at a power factor .8591
Answer: 44,5%
2. Calculate the percent efficiency when the load is 125 Kva at a power factor of .8764
Answer: 9-20%
3. Calculate the percent efficiency when the load is 77.5519 Kw at a power factor of .6863
Answer: 76.98%
4. Calculate the Kva load at a power factor of .5462 when the efficiency is a maximum, and the maximum
efficiency?
Answer: 7.5%
5. If the eddy current loss is 30% of the core loss, calculate its core loss if the transformer is connected to a source
of 6880 volts 70 cycle.
Answer:
201.14W
6. If thereddy current loss is 30% of the core loss, calculate its core loss if the transformer is connected to a source
of 8600 volts 60 cycle.
Answer:
369.576
7. If the eddy current loss is 30% of the core loss, calculate its core loss if the transformer is connected to a source
of 6880 volts 60 cycle.
Answer:
263.350
8. If the transformer operates with the following loads during the 24 hr period:
1.5 times rated Kva, power factor - 0.8, 1 hr; 1.25 times rated Kva, power factor-0.8, 2 hr; rated Kva, power factor
1.0, 3 hr; 1/2 rated Kva, power factor 1, 6 hr.; 1/4 rated Kva, power factor 1, 8 hr; no load 4 hr. calculate the all-
day efficiency
Answer:
99.4%
Solution
1.) 120 kva
8600/2400
TO CYCLE
Copin = 240V i POK= 295N
CSPORT = 185 √ iP₁²= 655 W₁lcc = 13.95349
% E = ?
Isc "R₁ = Pc
% E = (1 - WATTI LONCES
WATTS OUT TUT + WATTS LOCKET
Kvane = KUAY PC
PCC
=)
= 120 1295
X 100
Transcribed Image Text:Set 25 GEECKEY C. Rajo The following information is given in connection with test performed on a 120 Kva 8600/240 volt 70 cycle transformer: Name: Open circuit test..... 240 volts; Poc=295 watts Short circuit test.... 185 volts; Psc= 655 watts; Isc 13.95349 amps 1. Calculate the percent efficiency when the transformer is delivering rated kva at a power factor .8591 Answer: 44,5% 2. Calculate the percent efficiency when the load is 125 Kva at a power factor of .8764 Answer: 9-20% 3. Calculate the percent efficiency when the load is 77.5519 Kw at a power factor of .6863 Answer: 76.98% 4. Calculate the Kva load at a power factor of .5462 when the efficiency is a maximum, and the maximum efficiency? Answer: 7.5% 5. If the eddy current loss is 30% of the core loss, calculate its core loss if the transformer is connected to a source of 6880 volts 70 cycle. Answer: 201.14W 6. If thereddy current loss is 30% of the core loss, calculate its core loss if the transformer is connected to a source of 8600 volts 60 cycle. Answer: 369.576 7. If the eddy current loss is 30% of the core loss, calculate its core loss if the transformer is connected to a source of 6880 volts 60 cycle. Answer: 263.350 8. If the transformer operates with the following loads during the 24 hr period: 1.5 times rated Kva, power factor - 0.8, 1 hr; 1.25 times rated Kva, power factor-0.8, 2 hr; rated Kva, power factor 1.0, 3 hr; 1/2 rated Kva, power factor 1, 6 hr.; 1/4 rated Kva, power factor 1, 8 hr; no load 4 hr. calculate the all- day efficiency Answer: 99.4% Solution 1.) 120 kva 8600/2400 TO CYCLE Copin = 240V i POK= 295N CSPORT = 185 √ iP₁²= 655 W₁lcc = 13.95349 % E = ? Isc "R₁ = Pc % E = (1 - WATTI LONCES WATTS OUT TUT + WATTS LOCKET Kvane = KUAY PC PCC =) = 120 1295 X 100
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