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Series RL impedance angle, 0z = tan X!R 90 R-6n Va-6Vp Vy- 10 Vp V - V- 10 V -8Vp 1-1A V- I-6 v (b)

Series RL impedance angle, 0z = tan X!R 90 R-6n Va-6Vp Vy- 10 Vp V - V- 10 V -8Vp 1-1A V- I-6 v (b)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Discussion 1- Explain why the phasor and the impedance have the same angle. 2- At what condition the following results obtained? a- Phase angle equal zero b- The applied voltage leads the current by 90°. c- The average power equal to zero. 3- In general, how would the phasor diagram of Figure 4.1 change if the frequency was raised? 4- In general, how would the phasor diagram of Figure 4.2 change if the frequency was lowered? Series RL impedance angle, 0z= tanX,!R 90 R-6n (V v-6Vp Vr- 10 Vp v.10 V v-8Vp 1-1A V- I-6 Vv (a) (b) Fig.4-1 (a) Series circuit diagram, (b) VI phasor diagram 4-1.41 A (a) Fig.4-2 (a) Parallel circuit diagram, (b) VI phasor diagram
Transcribed Image Text:Discussion 1- Explain why the phasor and the impedance have the same angle. 2- At what condition the following results obtained? a- Phase angle equal zero b- The applied voltage leads the current by 90°. c- The average power equal to zero. 3- In general, how would the phasor diagram of Figure 4.1 change if the frequency was raised? 4- In general, how would the phasor diagram of Figure 4.2 change if the frequency was lowered? Series RL impedance angle, 0z= tanX,!R 90 R-6n (V v-6Vp Vr- 10 Vp v.10 V v-8Vp 1-1A V- I-6 Vv (a) (b) Fig.4-1 (a) Series circuit diagram, (b) VI phasor diagram 4-1.41 A (a) Fig.4-2 (a) Parallel circuit diagram, (b) VI phasor diagram
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