Series Capacitors - Percentage You have a circuit with a battery hooked up a voltage of 4.8 V. The capacitors have a value of C1 = 80.0 µF and C2 = 30.0 µF. 2 capacitors in series. The battery has While finding the actual voltage is very helpful, it's hard to use this as a prediction because not all batteries are the same. So one way to look at this is a percentage. Even if the voltage of the battery is different, the percentage of the voltage should be the same regardless. Find the percentage of the battery voltage that is across capacitor 1. To find percentages: • Find the voltage across the specific capacitor just like previously • Divide this voltage by the voltage of the battery • Multiply your answer by 100 to turn it into a percent Your answer should include: 2 Decimal Places Correct SI Units Your Answer:

Series Capacitors - Percentage You have a circuit with a battery hooked up a voltage of 4.8 V. The capacitors have a value of C1 = 80.0 µF and C2 = 30.0 µF. 2 capacitors in series. The battery has While finding the actual voltage is very helpful, it's hard to use this as a prediction because not all batteries are the same. So one way to look at this is a percentage. Even if the voltage of the battery is different, the percentage of the voltage should be the same regardless. Find the percentage of the battery voltage that is across capacitor 1. To find percentages: • Find the voltage across the specific capacitor just like previously • Divide this voltage by the voltage of the battery • Multiply your answer by 100 to turn it into a percent Your answer should include: 2 Decimal Places Correct SI Units Your Answer:

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

### Series Capacitors - Percentage

You have a circuit with a battery hooked up to 2 capacitors in series. The battery has a voltage of **4.8 V**. The capacitors have a value of **C1 = 80.0 μF** and **C2 = 30.0 μF**.

While finding the actual voltage is very helpful, it's hard to use this as a prediction because **not all batteries are the same**. So one way to look at this is a percentage. Even if the voltage of the battery is different, the percentage of the voltage should be the same regardless. Find the **percentage of the battery voltage that is across capacitor 1**.

To find percentages:
- Find the **voltage across the specific capacitor** just like previously
- Divide this voltage **by the voltage of the battery**
- Multiply your answer by **100 to turn it into a percent**

**Your answer should include:**
- 2 Decimal Places
- Correct **SI Units**

**Your Answer:**

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