Please give me the correct answer. 7. At what distance ofseparation must two 1.00-microCoulomb charges bepositioned in order for therepulsive force between themto be equivalent to the weight(on Earth) of a 1.00-kg mass?(NO SOLUTIONS REQUIRED)substitution into the Coulomb's law equation. Thefollowing unit equivalencies will assist in suchconversions.1 Coulomb = 106 microCoulomb1 Coulomb = 10° nanoCoulombThe problem-solving strategy used in Example Aincluded three steps:1. Identify and list known information in variableform.2. List the unknown (or desired) information invariable form.3. Substitute known values into the Coulomb'slaw equation and using proper algebraic stepsto solve for the unknown information. (In somecases and for some students, it might be easierto first do the algebra using the variables andthen perform the substitution as the last step.)>

Given: The value of charge is q=1.00 μC. The value of mass is m=1.00 kg. The formula to calculate…

Answered: separation must two 1.00- microCoulomb…

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separation must two 1.00- microCoulomb charges be positioned in order for the repulsive force between them to be equivalent to the weight (on Earth) of a 1.00-kg mass?