Select whether there is no work done by the system, work done by the system or work done by thesurroundings for each system described below:A. 4 NH3(g) + 5 O2(g) > 4 NO (g) + 6 H20(1) AH = -906 kJ/mol[ Select ]B. 2 NO (g) + 02 (g) 2 NO2(g) AH = -114.1 kJ/mol[ Select ]C. CI (g) + O3 (g) → CIO(g) + O2(g) AH = -163 kJ/mol[ Select ]D. CaCO3 (s) → CaO (s) + CO2(g) AH = 110.1 kJ/mol [ Select ]E. H20 (I) → H20 (g) AH = 44.0 kJ/mol [Select ]>>>>>

Answered: Select whether there is no work done by…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

Select whether there is no work done by the system, work done by the system or work done by the
surroundings for each system described below:
A. 4 NH3(g) + 5 O2(g) > 4 NO (g) + 6 H20(1) AH = -906 kJ/mol
[ Select ]
B. 2 NO (g) + 02 (g) 2 NO2(g) AH = -114.1 kJ/mol
[ Select ]
C. CI (g) + O3 (g) → CIO(g) + O2(g) AH = -163 kJ/mol
[ Select ]
D. CaCO3 (s) → CaO (s) + CO2(g) AH = 110.1 kJ/mol [ Select ]
E. H20 (I) → H20 (g) AH = 44.0 kJ/mol [Select ]
>
>
>
>
>

Expert Solution

Step 1

According to the first law of thermodynamics for a chemical reaction, the work done by the system on the surrounding or work is done on the system by the surrounding depends on the change in the volume during the reaction. The work done in a chemical reaction is given by:

$w = - P ∆ V$

Where P is the external pressure and $∆ V$ is the change in the volume during the chemical reaction.

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions