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Select the equation of the parabola with vertex (3, 2) and directrix y=-1. O(x-3)² =12(y-2) ○ (x-3)² = 1 / (y-2) 1 ○ (x+3)² = // (y + 2) 12 O (x+3)² = 12(y+2)

Select the equation of the parabola with vertex (3, 2) and directrix y=-1. O(x-3)² =12(y-2) ○ (x-3)² = 1 / (y-2) 1 ○ (x+3)² = // (y + 2) 12 O (x+3)² = 12(y+2)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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□ 3. Use the following information to answer the given problem. Standard Equation: (x-h)² = 4p(y−k) Focus: (h,k+p) Directrix: y=k-p Axis: x = h Vertex: (h,k) Select the equation of the parabola with vertex (3,2) and directrix y = -1. ○ (x-3)² = 12(y-2) O (x-3)² = (y-2) 1 O ○ (x + 3)² = // (y + 2) 12 O (x+3)² = 12(y+2)
Transcribed Image Text:□ 3. Use the following information to answer the given problem. Standard Equation: (x-h)² = 4p(y−k) Focus: (h,k+p) Directrix: y=k-p Axis: x = h Vertex: (h,k) Select the equation of the parabola with vertex (3,2) and directrix y = -1. ○ (x-3)² = 12(y-2) O (x-3)² = (y-2) 1 O ○ (x + 3)² = // (y + 2) 12 O (x+3)² = 12(y+2)
2. Identify the vertex of a parabola with focus (5,8) and directrix y = 2. O (-5,4) O (-5,-11) ○ (5,4) O (5,5)
Transcribed Image Text:2. Identify the vertex of a parabola with focus (5,8) and directrix y = 2. O (-5,4) O (-5,-11) ○ (5,4) O (5,5)
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