Select the correct answer. Which piecewise function is shown on the graph? 6- 4- 2- -8 -6 -4 8. -2 -6- -8- O A. I < -2 f(x) x2 - 5, -2 < r <1 |2(=-2) - 3 , I > 1 ОВ. I < -2 f(x) 2 - 5, -2 < x <1 2(=-2) - 2, r > 1 OC. I < -2 f(x) = {12 + 5, -2 < * < 1 2(1+2) – 2, * > 1 OD. -5 * < -2 f(x) r2 + 5 , -2 < r < 1 |2(= +2) – 3, * > 1
Select the correct answer. Which piecewise function is shown on the graph? 6- 4- 2- -8 -6 -4 8. -2 -6- -8- O A. I < -2 f(x) x2 - 5, -2 < r <1 |2(=-2) - 3 , I > 1 ОВ. I < -2 f(x) 2 - 5, -2 < x <1 2(=-2) - 2, r > 1 OC. I < -2 f(x) = {12 + 5, -2 < * < 1 2(1+2) – 2, * > 1 OD. -5 * < -2 f(x) r2 + 5 , -2 < r < 1 |2(= +2) – 3, * > 1
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![**Question 3:**
**Select the correct answer.**
**Which piecewise function is shown on the graph?**
[Image Description]
*A graph shows a piecewise function consisting of three distinct parts:*
- The first part is a constant function equal to 5 for \( x \leq -2 \). It is represented by a horizontal line at \( y = 5 \) with a closed circle at the point \((-2, 5)\).
- The second part is the function \( x^2 - 5 \) for \( -2 < x < 1 \). This part is shown as a parabola opening upwards, starting from \( x = -2 \) (open circle at \((-2, -1)\)) to \( x = 1 \) (open circle at \((1, -4)\)).
- The third part is the function \( 2(x-2) - 3 \) for \( x \geq 1 \). It is represented by a linear line starting from the point \((1, -3)\) (closed circle) and increasing linearly.
[Answer Options]
A.
\[
f(x) =
\begin{cases}
5, & x \leq -2 \\
x^2 - 5, & -2 < x < 1 \\
2(x - 2) - 3, & x \geq 1
\end{cases}
\]
B.
\[
f(x) =
\begin{cases}
5, & x \leq -2 \\
x^2 - 5, & -2 < x < 1 \\
2(x - 2) - 2, & x \geq 1
\end{cases}
\]
C.
\[
f(x) =
\begin{cases}
5, & x \leq -2 \\
x^2 + 5, & -2 < x < 1 \\
2(x + 2) - 2, & x \geq 1
\end{cases}
\]
D.
\[
f(x) =
\begin{cases}
-5, & x \leq -2 \\
x^2 + 5, & -2 < x < 1 \\
2(x + 2) - 3, & x \geq](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcc6f3c32-694d-43a3-9d98-4837519070f4%2F4bc6e483-a9b9-4c3d-95bb-eddfe4c9e8f2%2Fp86jue7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 3:**
**Select the correct answer.**
**Which piecewise function is shown on the graph?**
[Image Description]
*A graph shows a piecewise function consisting of three distinct parts:*
- The first part is a constant function equal to 5 for \( x \leq -2 \). It is represented by a horizontal line at \( y = 5 \) with a closed circle at the point \((-2, 5)\).
- The second part is the function \( x^2 - 5 \) for \( -2 < x < 1 \). This part is shown as a parabola opening upwards, starting from \( x = -2 \) (open circle at \((-2, -1)\)) to \( x = 1 \) (open circle at \((1, -4)\)).
- The third part is the function \( 2(x-2) - 3 \) for \( x \geq 1 \). It is represented by a linear line starting from the point \((1, -3)\) (closed circle) and increasing linearly.
[Answer Options]
A.
\[
f(x) =
\begin{cases}
5, & x \leq -2 \\
x^2 - 5, & -2 < x < 1 \\
2(x - 2) - 3, & x \geq 1
\end{cases}
\]
B.
\[
f(x) =
\begin{cases}
5, & x \leq -2 \\
x^2 - 5, & -2 < x < 1 \\
2(x - 2) - 2, & x \geq 1
\end{cases}
\]
C.
\[
f(x) =
\begin{cases}
5, & x \leq -2 \\
x^2 + 5, & -2 < x < 1 \\
2(x + 2) - 2, & x \geq 1
\end{cases}
\]
D.
\[
f(x) =
\begin{cases}
-5, & x \leq -2 \\
x^2 + 5, & -2 < x < 1 \\
2(x + 2) - 3, & x \geq
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