Select all of the following that are members of this set: {a €N: a² - 1 is divisible by 4} × {b € Z: bis prime} (3,7) (5,5) (1,2) (8, 18) (7,8) (6,2)
Select all of the following that are members of this set: {a €N: a² - 1 is divisible by 4} × {b € Z: bis prime} (3,7) (5,5) (1,2) (8, 18) (7,8) (6,2)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![### Set Membership Problem
#### Problem Statement:
Select all of the following that are members of the set:
\[
\left\{ a \in \mathbb{N} : a^2 - 1 \text{ is divisible by } 4 \right\} \times \left\{ b \in \mathbb{Z} : b \text{ is prime} \right\}
\]
#### Choices:
- [ ] (3, 7)
- [ ] (8, 18)
- [ ] (5, 5)
- [ ] (7, 8)
- [ ] (1, 2)
- [ ] (6, 2)
#### Explanation:
1. **First set (Natural numbers):**
- The elements \(a\) in the first set must satisfy the condition that \(a^2 - 1\) is divisible by 4.
- To determine if a number \(a\) fits this condition, substitute \(a\) into the expression \(a^2 - 1\) and check if it is divisible by 4.
2. **Second set (Integers):**
- The elements \(b\) in the second set must be prime numbers.
- A prime number is a number greater than 1 that has no positive divisors other than 1 and itself.
#### Detailed Evaluation:
- **(3, 7):**
- For \(a = 3\), \(3^2 - 1 = 9 - 1 = 8\), which is divisible by 4.
- 7 is a prime number.
- Thus, (3, 7) is a member of the set.
- **(8, 18):**
- For \(a = 8\), \(8^2 - 1 = 64 - 1 = 63\), which is not divisible by 4.
- 18 is not a prime number.
- Thus, (8, 18) is not a member of the set.
- **(5, 5):**
- For \(a = 5\), \(5^2 - 1 = 25 - 1 = 24\), which is divisible by 4.
- 5 is a prime number.
- Thus, (5, 5) is a member of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b36e76c-f4a3-4d67-a6fb-4428ed1e8db2%2F2ff223b7-79d4-48b1-a192-95744b88c01e%2F2wg3w7b_processed.png&w=3840&q=75)
Transcribed Image Text:### Set Membership Problem
#### Problem Statement:
Select all of the following that are members of the set:
\[
\left\{ a \in \mathbb{N} : a^2 - 1 \text{ is divisible by } 4 \right\} \times \left\{ b \in \mathbb{Z} : b \text{ is prime} \right\}
\]
#### Choices:
- [ ] (3, 7)
- [ ] (8, 18)
- [ ] (5, 5)
- [ ] (7, 8)
- [ ] (1, 2)
- [ ] (6, 2)
#### Explanation:
1. **First set (Natural numbers):**
- The elements \(a\) in the first set must satisfy the condition that \(a^2 - 1\) is divisible by 4.
- To determine if a number \(a\) fits this condition, substitute \(a\) into the expression \(a^2 - 1\) and check if it is divisible by 4.
2. **Second set (Integers):**
- The elements \(b\) in the second set must be prime numbers.
- A prime number is a number greater than 1 that has no positive divisors other than 1 and itself.
#### Detailed Evaluation:
- **(3, 7):**
- For \(a = 3\), \(3^2 - 1 = 9 - 1 = 8\), which is divisible by 4.
- 7 is a prime number.
- Thus, (3, 7) is a member of the set.
- **(8, 18):**
- For \(a = 8\), \(8^2 - 1 = 64 - 1 = 63\), which is not divisible by 4.
- 18 is not a prime number.
- Thus, (8, 18) is not a member of the set.
- **(5, 5):**
- For \(a = 5\), \(5^2 - 1 = 25 - 1 = 24\), which is divisible by 4.
- 5 is a prime number.
- Thus, (5, 5) is a member of
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