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Let x be the number of acres planted with corn and let y be the number of acres planted with soybeans. Choose the correct inequality below. OA. 70x+60y > 4200, x ≥ 0, y 20 B. 70x+60y≤ 4200, x ≥ 0, y 20 OC. 70x+60y ≥ 4200, x ≥ 0, y 20 OD. 70x+60y <4200, x ≥ 0, y 20 Use the graphing tool to graph the inequality and the boundary lines representing he nonnegative constraints. Click to enlarge graph

Let x be the number of acres planted with corn and let y be the number of acres planted with soybeans. Choose the correct inequality below. OA. 70x+60y > 4200, x ≥ 0, y 20 B. 70x+60y≤ 4200, x ≥ 0, y 20 OC. 70x+60y ≥ 4200, x ≥ 0, y 20 OD. 70x+60y <4200, x ≥ 0, y 20 Use the graphing tool to graph the inequality and the boundary lines representing he nonnegative constraints. Click to enlarge graph

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Linear Inequalities in Farm Planning Seed costs for a farmer are $70 per acre for corn and $60 per acre for soybeans. How many acres of each crop should the farmer plant if she wants to spend no more than $4200 on seed? Express your answer as a linear inequality with appropriate nonnegative restrictions and draw its graph. **Problem Statement** Let \( x \) be the number of acres planted with corn and let \( y \) be the number of acres planted with soybeans. Choose the correct inequality below: - A. \( 70x + 60y > 4200, \, x \geq 0, \, y \geq 0 \) - B. \( 70x + 60y \leq 4200, \, x \geq 0, \, y \geq 0 \) (Correct Answer) - C. \( 70x + 60y \geq 4200, \, x \geq 0, \, y \geq 0 \) - D. \( 70x + 60y < 4200, \, x \geq 0, \, y \geq 0 \) Use the graphing tool to graph the inequality and the boundary lines representing the nonnegative constraints. **Graph Details** The graph provided shows two axes: - The x-axis represents the number of acres planted with corn, ranging from 0 to 100. - The y-axis represents the number of acres planted with soybeans, also ranging from 0 to 100. Both axes include a grid to facilitate plotting points. **Instructions for Graphing** 1. Identify the line \( 70x + 60y = 4200 \) by finding key points, such as the intercepts. 2. Plot the intercepts. - When \( x = 0 \), solve \( 60y = 4200 \) to get \( y = 70 \). - When \( y = 0 \), solve \( 70x = 4200 \) to get \( x = 60 \). 3. Draw the line through these points. 4. Shade the region below and including the line to represent the inequality \( 70x + 60y \leq 4200 \). **Graph Button** A button is available to enlarge the graph to facilitate a detailed view
Transcribed Image Text:### Linear Inequalities in Farm Planning Seed costs for a farmer are $70 per acre for corn and $60 per acre for soybeans. How many acres of each crop should the farmer plant if she wants to spend no more than $4200 on seed? Express your answer as a linear inequality with appropriate nonnegative restrictions and draw its graph. **Problem Statement** Let \( x \) be the number of acres planted with corn and let \( y \) be the number of acres planted with soybeans. Choose the correct inequality below: - A. \( 70x + 60y > 4200, \, x \geq 0, \, y \geq 0 \) - B. \( 70x + 60y \leq 4200, \, x \geq 0, \, y \geq 0 \) (Correct Answer) - C. \( 70x + 60y \geq 4200, \, x \geq 0, \, y \geq 0 \) - D. \( 70x + 60y < 4200, \, x \geq 0, \, y \geq 0 \) Use the graphing tool to graph the inequality and the boundary lines representing the nonnegative constraints. **Graph Details** The graph provided shows two axes: - The x-axis represents the number of acres planted with corn, ranging from 0 to 100. - The y-axis represents the number of acres planted with soybeans, also ranging from 0 to 100. Both axes include a grid to facilitate plotting points. **Instructions for Graphing** 1. Identify the line \( 70x + 60y = 4200 \) by finding key points, such as the intercepts. 2. Plot the intercepts. - When \( x = 0 \), solve \( 60y = 4200 \) to get \( y = 70 \). - When \( y = 0 \), solve \( 70x = 4200 \) to get \( x = 60 \). 3. Draw the line through these points. 4. Shade the region below and including the line to represent the inequality \( 70x + 60y \leq 4200 \). **Graph Button** A button is available to enlarge the graph to facilitate a detailed view
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