See Example 1 in Section 5.1. Now suppose that the region S is divided into 5 strips of equal width. Let each strip be approximated with a rectangle whose height is determined using a right endpoint. a) Find the sum of the areas of these 5 rectangles. R b) Which of the following is true? O R, underestimates the area of S O R, overestimates the area of S OR, equals the area of S

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See Example 1 in Section 5.1. Now suppose that the region S is divided into 5 strips of equal width. Let
each strip be approximated with a rectangle whose height is determined using a right endpoint.
a) Find the sum of the areas of these 5 rectangles.
R3 =
b) Which of the following is true?
O R, underestimates the area of S
O R, overestimates the area of S
O R, equals the area of S
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Transcribed Image Text:See Example 1 in Section 5.1. Now suppose that the region S is divided into 5 strips of equal width. Let each strip be approximated with a rectangle whose height is determined using a right endpoint. a) Find the sum of the areas of these 5 rectangles. R3 = b) Which of the following is true? O R, underestimates the area of S O R, overestimates the area of S O R, equals the area of S Question Help: O Message instructor D Post to forum Submit Question
V EXAMPLE 1 Estimating an area Use rectangles to estimate the area under the
parabola y = x' from 0 to 1 (the parabolic region S illustrated in Figure 3).
SOLUTION We first notice that the area of S must be somewhere between 0 and 1 because
S is contained in a square with side length 1, but we can certainly do better than that.
Suppose we divide S into four strips Sj, S2, S, and S, by drawing the vertical lines x = ;.
x = , and x = as in Figure 4(a).
FIGURE 3
у
f1,1)
(1,1)
y =
S,
S,
S,
S,
FIGURE 4
(a)
(b)
333
SECTION 5.1 AREAS AND DISTANCE!
we can approximate each strip by a rectangle whose base is the same as the strip and
whose height is the same as the right edge of the strip [see Figure 4(h)]. In other words,
the heights of these rectangles are the values of the function (() = x' at the right end-
points of the subintervals (0. J. [. }|. (:. :), and [;. 1].
Each rectangle has width and the heights are (}, (. (GY, and 1'. If we let R. be
the sum of the areas of these approximating rectangles, we get
R, = · (:)} + } · (C) + ! · G}' + ! • 1² = ; = 0,46875
From Figure 4(b) we see that the area A of S is less than Ra, so
A< 0.46875
Instead of using the rectangles in Figure 4(b) we could use the smaller rectangles in
Figure 5 whose heights are the values of f at the left endpoints of the subintervals. (The
lertmost rectangle has collapsed because its height is 0.) The sum of the areas of these
approximating rectangles is
y =r
L, = : 0° +: (' + : G} +! · () = = 0.21875
We see that the area of S is larger than L.. so we have lower and upper estimates for A:
0.21875 <A < 0.46875
We can repeat this procedure with a larger number of strips. Figure 6 shows what
happens when we divide the region S into eight strips of equal width.
FIGURE 5
Transcribed Image Text:V EXAMPLE 1 Estimating an area Use rectangles to estimate the area under the parabola y = x' from 0 to 1 (the parabolic region S illustrated in Figure 3). SOLUTION We first notice that the area of S must be somewhere between 0 and 1 because S is contained in a square with side length 1, but we can certainly do better than that. Suppose we divide S into four strips Sj, S2, S, and S, by drawing the vertical lines x = ;. x = , and x = as in Figure 4(a). FIGURE 3 у f1,1) (1,1) y = S, S, S, S, FIGURE 4 (a) (b) 333 SECTION 5.1 AREAS AND DISTANCE! we can approximate each strip by a rectangle whose base is the same as the strip and whose height is the same as the right edge of the strip [see Figure 4(h)]. In other words, the heights of these rectangles are the values of the function (() = x' at the right end- points of the subintervals (0. J. [. }|. (:. :), and [;. 1]. Each rectangle has width and the heights are (}, (. (GY, and 1'. If we let R. be the sum of the areas of these approximating rectangles, we get R, = · (:)} + } · (C) + ! · G}' + ! • 1² = ; = 0,46875 From Figure 4(b) we see that the area A of S is less than Ra, so A< 0.46875 Instead of using the rectangles in Figure 4(b) we could use the smaller rectangles in Figure 5 whose heights are the values of f at the left endpoints of the subintervals. (The lertmost rectangle has collapsed because its height is 0.) The sum of the areas of these approximating rectangles is y =r L, = : 0° +: (' + : G} +! · () = = 0.21875 We see that the area of S is larger than L.. so we have lower and upper estimates for A: 0.21875 <A < 0.46875 We can repeat this procedure with a larger number of strips. Figure 6 shows what happens when we divide the region S into eight strips of equal width. FIGURE 5
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