Section 3.1.3 described the phasor method of adding two sine waves (with the same properties except for different amplitude and phase). In the image here an application is presented. This represents the mathematics of superposition of waves scattered by approximately 30 adjacent atoms. The length of the green arrow represents the amplitude of the resultant wave. The pink circle represents the expected amplitude for the case of component waves with equal amplitude but random phase. Which of the statements below is the most likely explanation for the observation that the green arrow is significantly shorter than the radius of the circle? (Lecture 9 should help.) Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b O с The waves scattered by neighbouring atoms give random phase shifts but it is possible for the "random walk" in the phasor diagram to end close to the start point. It is just luck that the arrangement of the particular 30 atoms chosen gave a green arrow much shorter than the N average random walk. The atoms are probably in a low density gas. Scattering from adjacent atoms (in this case) gives neither identical nor random phase differences. Since many of the phase differences are similar to the average, the chain of white arrows tends to spiral around the start point and so the tip of the green arrow cannot be very far from it. Since the phase shifts for neighbouring atoms are fairly similar it is likely that the atoms form part of a liquid or high density gas. The results described above are exactly what you would expect for an ordered crystalline solid.
Section 3.1.3 described the phasor method of adding two sine waves (with the same properties except for different amplitude and phase). In the image here an application is presented. This represents the mathematics of superposition of waves scattered by approximately 30 adjacent atoms. The length of the green arrow represents the amplitude of the resultant wave. The pink circle represents the expected amplitude for the case of component waves with equal amplitude but random phase. Which of the statements below is the most likely explanation for the observation that the green arrow is significantly shorter than the radius of the circle? (Lecture 9 should help.) Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b O с The waves scattered by neighbouring atoms give random phase shifts but it is possible for the "random walk" in the phasor diagram to end close to the start point. It is just luck that the arrangement of the particular 30 atoms chosen gave a green arrow much shorter than the N average random walk. The atoms are probably in a low density gas. Scattering from adjacent atoms (in this case) gives neither identical nor random phase differences. Since many of the phase differences are similar to the average, the chain of white arrows tends to spiral around the start point and so the tip of the green arrow cannot be very far from it. Since the phase shifts for neighbouring atoms are fairly similar it is likely that the atoms form part of a liquid or high density gas. The results described above are exactly what you would expect for an ordered crystalline solid.
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Transcribed Image Text:Section 3.1.3 described the phasor method of adding two sine waves (with the
same properties except for different amplitude and phase). In the image here an
application is presented. This represents the mathematics of superposition of
waves scattered by approximately 30 adjacent atoms. The length of the green
arrow represents the amplitude of the resultant wave. The pink circle represents
the expected amplitude for the case of component waves with equal amplitude
but random phase.
Which of the statements below is the most likely explanation for the observation
that the green arrow is significantly shorter than the radius of the circle?
(Lecture 9 should help.)
Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.
a
b
O
с
The waves scattered by neighbouring atoms give random phase shifts but it is possible for the "random walk" in the phasor diagram
to end close to the start point. It is just luck that the arrangement of the particular 30 atoms chosen gave a green arrow much shorter
than the N average random walk. The atoms are probably in a low density gas.
Scattering from adjacent atoms (in this case) gives neither identical nor random phase differences. Since many of the phase
differences are similar to the average, the chain of white arrows tends to spiral around the start point and so the tip of the green
arrow cannot be very far from it. Since the phase shifts for neighbouring atoms are fairly similar it is likely that the atoms form part of
a liquid or high density gas.
The results described above are exactly what you would expect for an ordered crystalline solid.
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