Second Question: Assume block size B-8, N=4, encryption is made by K bit circular left shift, K-3. Encrypt the message "AB67C8D2", note that IV=CD. Provide all details of your calculations. K 3 bits) Time = 1 D₁ (8 bits) Encrypt 0₁ (8 bits) K- Time=2 D₂ Encrypt 0₂ K-> Time = N-1 DN-1 Encrypt ON-1 K-> Time = N DN Encrypt ON (8 bits)
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- Use the encryption congruence C = (3P + 7) mode 26 to encode the message EASYLet M be the plaintext message M = MALAYSIA and the private key, K = ISSOGOOD Convert this plaintext and key message to Hexadecimal representation using the ASCII table. Convert the Hexadecimal representation to binary number. Represent your plaintext binary number as a form of a block, using the DES encryption technique (2 equal blocks). Using the initial permutation (table is provided below), please provide your plaintext output. Using the expansion P-box (table is provided below), show the plaintext output of this process. For the key: Using the key permutation table (provided below), show the output of this conversion process. Using the appropriate steps of DES operation, what is the final output of the key for round 1 (hint: you have to use the circular left shift and permutation compression (PC) table provided below). For round 1, please provide your output for the XOR operation of plaintext and the key, according to the DES operation. Based on the output of 4(h), explain the…You have an originating plain text message (in hexadecimal): 41 72 61 62 Use your Student ID number to obtain a 10-bit key as follows: Key (in decimal) = (ID mod 1024) +1.You have to manually cipher the first block of the following plain text message (first 8 bits). The encrypting process will be done using Simplified DES (S-DES). you must explain all steps in details [mandatory: write down all the calculations].
- You are given the following parameters in RSA cryptosystem: p = 11, q = 13, e = 13 a) Find the integer d. b) List down the public key and private key. You need to encrypt the plaintext message, M = OF. c) Convert this message to value according to ASCII table. To encrypt this message, you can either combine the value, or separate it into the blocks of 2 digits (Hint: it must satisfy the condition M < n). d) Encrypt and decrypt the message OF. e) If the decimal value (not character) of ciphertext is 188267, decrypt this value and convert it to an appropriate message according to the ASCII table.You have an originating plain text message (in hexadecimal): 41 72 61 62 Use your Student ID number to obtain a 10-bit key as follows: Key (in decimal) = 666. You have to manually cipher the first block of the following plain text message (first 8 bits). The encrypting process will be done using Simplified DES (S-DES). you must explain all steps in detailsCan you please show the shifts for the encrypt & decrypt in this format? For example, like this : Example:ABCDEFGHIJKLMNOPQRSTUVWXYZ Row 1FGHIJKLMNOPQRSTUVWXYZABCDE Row 2 If the plaintext to encrypt is:THIS IS THE ANSWER The ciphertext becomes:YMNX NX YMJ FSXBJW This is for me to help understand and to redo the problem for studying. Thank you!!
- Let M be the plaintext message M = MALAYSIA and the private key, K || ISSOGOOD a) Represent your plaintext binary number as a form of a block, using the DES encryption technique (2 equal blocks). b) Using the initial permutation (table is provided below), please provide your plaintext output. Initial Permutation Initial Permutation 58 50 42 34 26 18 10 02 60 52 44 36 28 20 12 04 62 54 46 38 30 22 14 06 64 56 48 40 32 24 16 08 57 49 41 33 25 17 09 01 59 51 43 35 27 19 11 03 61 53 45 37 29 21 13 05 63 55 47 39 31 23 15 07The following figure is the Cipher Block Chaining (CBC) mode to encrypt large messages. Which of the followings statement is *correct* regarding this mode? IV m₁ m₂ m3 C3 m4 C4 m5 C5 If a message contains two identical 64-bit blocks, the corresponding ciphertext blocks are also identical. Switching the order of two cipher blocks will not cause any detectable error in the plaintext. Duplicating a cipher block will not cause any detectable error in the plaintext. Deleting a cipher block will cause some detectable error in the plaintext. m6 E encrypt with secret key C63. Suppose the key k to DES is k = (0E329232E A6D0D73)hez. Find kį and k2. Also, given m = (0000000000000000)her, find Lo, Ro, L1, R1.
- Only. Q1A symmetric block encryption algorithm is shown below. 16-bit blocks of plaintext P are encrypted using a 32-bit key. Encryption is defined as: C = (P EX_OR Ko) + K1 C is the ciphertext, K is the secret key, Ko is the leftmost 16 bits of K, K1 is the rightmost 16 bits of K, EX_OR is bitwise exclusive OR, and + is binary addition. a. The ciphertext C must be the same size as the plaintext P, that is, it must not be larger than 16 bits. How can this be achieved? b. Show the decryption equation. How will the encrypted message be decrypted?] You receive a message that was encrypted using the RSA system with public key (43, 143), where 43 is the public exponent. A message encrypted using this cryptosystem was captured by an enemy and consisted of the following numbers: 6 82 132 115. Can you decipher what was the original message? (Hint: As a first step, you need to find p and q.)