Second Hand Smoke: Cotinine levels were measured in a group of 40 non-smokers exposed to tobacco smoke. The mean of the sample is 60.56 mg/ml and the standard deviation is 138.08 mg/ml Also Cotinine levels were measure in a group of 40 non-smokers not exposed to tobacco smoke and the mean of the sample is 16.35 mg/ml and the standard deviation is 62.53 mg/ml. Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed in the body, cotinine is produced. use a 0.05 significance level to test the claim that non-smokers exposed to tobacco smoke have a higher nicotine level than non-smokers not exposed to tobacco smoke. Construct an appropriate confhdence interval for the hypothesis test in problem a) Confidence Interval b) Conclusion

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A: The provided information is as follows:The average birth weight of a domestic cat is 4 ounces.The…

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A: The properties of the normal distribution is,   The Normal distribution curve is and bell shaped…

Q: Blood sugars from eight patients in a rural clinic were recorded last summer by the local physician.…

A: Given blood sugar results are120,145,200,250,79,100,894,255sample size(n)=8

Q: n the state of Ohio, data has shown that 9% of adults are illiterate (lack basic reading and writing…

A: Solution: Given information: n1=300 Sample size of adults from Alabama n2=250 Sample size of adults…

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A: given data normal distributionμ = 38 inchesσ = 2 inchesfor x = 42 inchespercentile = ?

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A: Obtain the 90% confidence interval for the population mean.   The 90% confidence interval for the…

Q: z-score Percentile z-score Percentile z-score Percentile -3.0 0.13 -2.0 2.28 -1.0 15.87 -2.9 0.19…

A: It is given that  Mean = 24.8 Standard deviation = 2.5 Z-Score, Z = ( X - μ )/σ

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A: 69.5 2.62 64.4 2.53 American woman:

Q: The mean height for women in the United States is approximately 64.5 inches with a standard…

A: Formula : Z =(X - μ)/σ

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A:

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A: Introduction :-  We have to compare the relative variability of age and income. We will compare the…

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A: Given information: μ=68.3, σ=2.9 The P-value for the 96th percentile = 0.96 Determine the z-score…

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A:

Q: Use the Empirical Rule. The mean speed of a sample of vehicles along a stretch of highway is 65…

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A:

Q: In a standardized exam the mean score is 400 with a standard deviation of 50. Assume the scores…

A: Solution

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Q: On a standardized exam, the score are normally distributed with a mean of 300 and a standard…

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Q: the Empirical Rule. The mean speed of a sample of vehicles along a stretch of highway is 70 miles…

A:

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A: Empirical rule is used in statistics and probability.

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Q: A mandatory competency test for high school sophomores has a normal distribution with a mean of 470…

A:

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A:

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A: