sec (In x) + sec2(In x) tan(In x) dx Given: 2x Find: du

Q: 8+tan x dx 1-sin?x i.

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Q: Determine 3 sec(9x) tan (9x) dx

A: We have to determine the value of integral: ∫3 sec 9x tan 9x dx Solving given indefinite integral by…

Q: Evaluate sin dx

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Q: Differentiate. V = 3 - sec(x) tan(x)

A: The given function y is in the quotient form. Apply the quotient rule formula

Q: , 8 tan² (2x) dx

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Q: 2- S tan x dx.

A: Given integral is: I=∫0πtan x dx We have to evaluate this integral.

Q: sin(tan x) cos²x Evaluate ·[³ dx.

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Q: Using appropriate substitution, [sec (2x) + 1] tan(2x) dx is equal to

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Q: f(x) = 2 tan x Ꮖ

A: f(x)=2tan⁡xx

Q: Find a suitable substitution for evaluating ∫tan x sec2 x dx andexplain your choice.

A: we have to integrate the following integral using a suitable substitution. ∫tanx.sec2xdx

Q: Evaluate y' for the given functions and simplify your answers a.y = sin(6x - 5) sin (6x + 5)

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Q: Evaluate sec x dx VIn(sec x + tan x)

A: We will let,  ln( sec x+tan x) = t  to solve this question.

Q: J + tan x)² sec x dx

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Q: (sec x + tan x)² dx

A: It is basic integration problem  First I have used whole square formula then integrate.

Q: sec2 x tan ydx + sec² y tan xdy = 0.

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Q: 9. sec(1- x) tan(1 – x) dx

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Q: sec² (x) tan° (x)dx

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Q: tanx sec² x.dx COS X √√2+ sin x dx

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Q: y = Secx ( sinx+ Cosx)

A: Given, y=secxsinx+cosx And we have to find the dydx.