Please only answer Q64. Thank you! ### Problem 63. Seasonal Sales**Context:**The average number of guests visiting the Magic Kingdom at Walt Disney World per day is modeled by the function:\[ n(x) = 30,000 + 20,000 \sin\left( \frac{\pi}{2} (x + 1) \right) \]where \( n \) is the number of guests and \( x \) is the month. **Question:**If January corresponds to \( x = 1 \), how many people on average are visiting the Magic Kingdom per day in February?**Solution:**To find the average number of guests in February, we substitute \( x = 2 \) into the given function.\[ n(2) = 30,000 + 20,000 \sin\left( \frac{\pi}{2} (2 + 1) \right) \]\[ n(2) = 30,000 + 20,000 \sin\left( \frac{3\pi}{2} \right) \]Since \(\sin\left( \frac{3\pi}{2} \right)\) is -1:\[ n(2) = 30,000 + 20,000 (-1) \]\[ n(2) = 30,000 - 20,000 \]\[ n(2) = 10,000 \]Thus, on average, 10,000 guests are visiting the Magic Kingdom per day in February.### Problem 64. Seasonal Sales**Question:**How many guests are visiting the Magic Kingdom in Exercise 63 in December?**Solution:**To find the number of guests in December, we note that December corresponds to \( x = 12 \). Substituting \( x = 12 \) into the function:\[ n(12) = 30,000 + 20,000 \sin\left( \frac{\pi}{2} (12 + 1) \right) \]\[ n(12) = 30,000 + 20,000 \sin\left( \frac{13\pi}{2} \right) \]Since \(\sin\left( \frac{13\pi}{2} \right)\) is 1:\[ n(12) = 30,000 + 20,000 (1) \]\[ n(12

Name: Please only answer Q64. Thank you! ### Problem 63. Seasonal Sales**Con
Uploaded: 2024-03-20T06:46:14.000Z
Channel: Bartleby
Description: Please only answer Q64. Thank you! ### Problem 63. Seasonal Sales**Context:**The average number of guests visiting the Magic Kingdom at Walt Disney World per day is modeled by the function:\[ n(x) = 30,000 + 20,000 \sin\left( \frac{\pi}{2} (x + 1) \r