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Sea 2z(z+1) H(z) = (2-X2²X2²+42+5) Los polos son Seleccione una: O a. z = 137,2= + 1/2 ₁2 = -2±j Z = z O b. z= - ₁2=j=1/₁2 = -2±j , z O c. Z= z = -13 ₁² z = tj ²/2 tj-/2, z = 2 tj O d. 2-3,2-4/12--22/ = -2±j Z = O e. 2--2--2--21 =

Sea 2z(z+1) H(z) = (2-X2²X2²+42+5) Los polos son Seleccione una: O a. z = 137,2= + 1/2 ₁2 = -2±j Z = z O b. z= - ₁2=j=1/₁2 = -2±j , z O c. Z= z = -13 ₁² z = tj ²/2 tj-/2, z = 2 tj O d. 2-3,2-4/12--22/ = -2±j Z = O e. 2--2--2--21 =

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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the poles are:

Sea 2z(z+1) H(z)= (2-)(2²+)(2²+42+5) Los polos son Seleccione una: 1 0 O a. z= 2.2--₁2-₁2--24j Z = z = −2+j O b. 2--₁2-12--2+j = = tj z= z OG. Z=-1₁2=1/112=21/ c. 3 O d. 2-1.2- =j₁2--2+j z = 2= Z = z tj O e. Z= 2 = − 1 ² ₁ 2 = ± √ 12 ₁ ² z = ±j, z = -2±j
Transcribed Image Text:Sea 2z(z+1) H(z)= (2-)(2²+)(2²+42+5) Los polos son Seleccione una: 1 0 O a. z= 2.2--₁2-₁2--24j Z = z = −2+j O b. 2--₁2-12--2+j = = tj z= z OG. Z=-1₁2=1/112=21/ c. 3 O d. 2-1.2- =j₁2--2+j z = 2= Z = z tj O e. Z= 2 = − 1 ² ₁ 2 = ± √ 12 ₁ ² z = ±j, z = -2±j
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