**Which is most acidic?**This image presents five chemical structures labeled from 1 to 5, each featuring a thiol group (-SH). The task is to determine which compound is the most acidic. Let's examine each compound:1. **Structure 1**: A simple alkane with an -SH group, featuring an iodine (I) substituent on a carbon atom adjacent to the -SH group. 2. **Structure 2**: An alkane with an -SH group, featuring a single chlorine (Cl) atom on a carbon adjacent to the -SH group. 3. **Structure 3**: An alkane with an -SH group, featuring two chlorine (Cl) atoms on a carbon adjacent to the -SH group. 4. **Structure 4**: An alkane with an -SH group, featuring two chlorine (Cl) atoms, each on separate carbon atoms adjacent to the -SH group.5. **Structure 5**: An alkane with an -SH group, featuring three chlorine (Cl) atoms, two on one carbon and one on another carbon adjacent to the -SH group.To determine acidity, consider the electron-withdrawing effects of substituents:- Electron-withdrawing groups such as chlorine can increase acidity by stabilizing negative charge on the conjugate base.- Multiple chlorine atoms will increase this effect.Therefore, more chlorine atoms near the thiol likely increase the acidity: Structure 5, which has three chlorines, is expected to be the most acidic.

Answer:Presence of -I effect group increases the strength of the acid and it can do so on these…

Answered: се Which is most acidic? SH SH I 1 се 4…

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се Which is most acidic? SH SH I 1 се 4 SH cl 2 c cl SH Ÿ 5 SH се се 3

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Which is most acidic?**

This image presents five chemical structures labeled from 1 to 5, each featuring a thiol group (-SH). The task is to determine which compound is the most acidic. Let's examine each compound:

1. **Structure 1**: A simple alkane with an -SH group, featuring an iodine (I) substituent on a carbon atom adjacent to the -SH group.

2. **Structure 2**: An alkane with an -SH group, featuring a single chlorine (Cl) atom on a carbon adjacent to the -SH group.

3. **Structure 3**: An alkane with an -SH group, featuring two chlorine (Cl) atoms on a carbon adjacent to the -SH group.

4. **Structure 4**: An alkane with an -SH group, featuring two chlorine (Cl) atoms, each on separate carbon atoms adjacent to the -SH group.

5. **Structure 5**: An alkane with an -SH group, featuring three chlorine (Cl) atoms, two on one carbon and one on another carbon adjacent to the -SH group.

To determine acidity, consider the electron-withdrawing effects of substituents:
- Electron-withdrawing groups such as chlorine can increase acidity by stabilizing negative charge on the conjugate base.
- Multiple chlorine atoms will increase this effect.

Therefore, more chlorine atoms near the thiol likely increase the acidity: Structure 5, which has three chlorines, is expected to be the most acidic.

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Step 1: -I effect and the strength of acid!

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