se variation of parameters to find a general solution to the differential equation given that the functions y, and y, are linearly independent solutions to the corresponding homogeneous quation for t> 0. ty" + (5t – 1)y' – 5y = t² e - 5t. y, = 5t – 1, Y2 =e - 5t general solution is y(t) =

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Use variation of parameters to find a general solution to the differential equation given that the functions y, and y, are linearly independent solutions to the corresponding homogeneous
equation for t> 0.
ty" + (5t – 1)y' - 5y = t? e - 5t.
y1 = 5t – 1,
Y2 = e
- 5t
A general solution is y(t) =
Transcribed Image Text:Use variation of parameters to find a general solution to the differential equation given that the functions y, and y, are linearly independent solutions to the corresponding homogeneous equation for t> 0. ty" + (5t – 1)y' - 5y = t? e - 5t. y1 = 5t – 1, Y2 = e - 5t A general solution is y(t) =
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