se the Standard Normal Table or technology to find the z-score that corresponds to the cumulative area 0.0006 Z= www (Type an integer or decimal rounded to two decimal places as needed.)
Q: Use the standard normal table to find the z-score that corresponds to the cumulative area 0.9934. If…
A: Draw the normal curve and shade the area of 0.9934 to the left of z.
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A: Solution: Let Z be the standard normal variable with mean 0 and standard deviation 1. Z~N(0,1)
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Q: Suppose the lengths of human pregnancies are normally distributed with u = 266 days and a = 16 days.…
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A: Using the below standard Normal table
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A: From the provided information, The area to the left of z is 0.0250 that is P (Z<z) = 0.0250
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A: P(Z<z)=0.80
Q: Find the indicated z-score shown in the graph to the right. area =0.0446
A: The z-score to the right area of 0.0446 is, PZ>z=0.04461-PZ<z=0.0446PZ<z=1-0.0446=0.9554…
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A: For each -score below, find the area between the mean and the -scorea) b) .
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A: Given that, p-value = 85% = 0.85
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- Use the standard normal table to find the z-score that corresponds to the cumulative area 0.9616. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.) - X - X Standard normal table (page 1) Standard normal table (page 2) - 3.3 .0004 0005 .0003 .0004 .0004 .0004 .0004 .0004 .0005 .0005 .0005 0.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 - 3.2 .0005 .0005 .0006 .0006 .0006 .0006 .0006 .0007 .0007 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 3.1 .0007 .0007 .0008 .0008 .0008 .0008 .0009 .0009 .0009 .0010 0.4 .6554 .6591 .6628 .6700 .6736 .6772 .6808 .6844 .6879 .6664 - 3.0 – 2.9 .0010 .0010 .0011 .0011 .0011 .0012 .0012 .0013 .0013 .0013 .6915 .7019 .7088 .7422…Find the area above 29 for a N(15,5) distributionUse the TI-B4 calculator to find the z-score for which the area to its left is 0.12. Round the answer to two decimal places, The z-score for the given area is
- determine the z-score that corresponds to a cumulative area of 0.4801Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0129. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decipaall eaundad to thcee deeisel elese apeaded - X Standard normal table (page 2) Standard normal table (page 1) Standard Normal Distribution Standard Normal Distribution Critical Values Critical Values Level of Confidence c Level of Confidence c 0.80 1.28 0.80 1.28 0.90 1.645 Area 0.90 1.645 0.95 1.96 0.95 1.96 0.99 2.575 0.99 2.575 .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .09 .08 .07 .06 05 .04 .03 .02 .01 .00 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 - 3.4 - 3.3 - 3.2 - 3.1 - 3.0 - 2.9 .0002 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0.1 .5398 .5438 .5478 .5517…can you please find the area of the left of 2.3451 for z score....
- Please round to 5 decimal placesUse the standard normal table to find the z-score that corresponds to the cumulative area 0.9945 If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.)The mean height of women in a country (ages 20 - 29) is 64.3 inches. A random sample of 70 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 inches? Assume o = 2.86. The probability that the mean height for the sample is greater than 65 inches is (Round to four decimal places as needed.)
- 1. Find the area between a z-score of -0.41 and 1.7. 2. FInd the area between a z-score of -0.41 and 0.Find the areas for the following z values. Use standard normal table. Provide your answers to four decimal places (4 dp.) (a) Area to the left of z= -0.25 - (b) Area to the right of z =1.23 - (c) Area to the right of z=-2.97 - (d) Area to the left of z=0.00 - (e) Area to the left of z=2.33 - ii) Using your calculator in STAT MODE, find the mean and standard deviation of the following sample for the variable age (Round to 3 dp). 18 18 20 20 23 25 29 35 Mean : Standard Deviation :