se method of refuction of order to find a second solution y2(x). Given that y1(x)=ex is a solution. (x(4)-4x)y'' + (4-x(4))y' + (4x-4)y =0

Q: solve y(4)-3y'''+2y''=e3x  using undetermined coefficient

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Q: Find the general solution by undetermined coefficients.  y'' + y = 2x2e-x.

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Q: 40e5*, y(0) = ;, y'(0) =y"(0) 9. y" – 2y" + y' = 2 – 24e* + 2

A: Given: y'''-2y''+y' = 2-24ex+40e5x, y(0) = 12, y'(0)=52, y''(0)=-92

Q: 2. Solve X' - 3x – 4x+12 2 0 algebraically (number line)

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Q: Solve x = - " 3x x 3x y= 4y + 2z у + 2y || || || 4 2 2 11 с

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Q: Find the solution of 4x²y" - 6x²y + y = 0, x > 0 of the form Y₁ = x¹(1+₁x + €₂x² + 3x³ + ...) Enter…

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Q: Solve (x-1)' +(x-2)'+(x - 3)' +(x + 4)' +(x + 5)' = 0

A: The solution for the above question is as shown below.

Q: Solve 1 0-²40 = 5 x (0) = - 4, y(0) = 10

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Q: -[3x+(8x+1)]=6-(2x+4) Linear equation with on variable

A: Given,

Q: Solve [3] - [ -50 = -13] [0] x(0) 30 - x (t) = y(t) = Question Help: Message instructor Submit…

A: Solving by matrix method