se Euler's method with step size 0.5 to compute the approximate y-values Y1, Y2, Y3, and y4 of the olution of the initial-value problem -' = 1 + 3x + 2y, y(0) = 0. 1 = 2 3 = 4= Check Answer I| ||

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### Euler's Method for Solving Initial-Value Problems

This section will guide you through using Euler's method to compute approximate solutions for an initial-value problem.

#### Problem Statement
We are given the differential equation:

\[ y' = 1 + 3x + 2y \]

with the initial condition:

\[ y(0) = 0 \]

Using Euler's method with a step size \( h = 0.5 \), we need to compute the approximate \( y \)-values \( y_1, y_2, y_3 \), and \( y_4 \).

Euler's method formula can be written as:
\[ y_{n+1} = y_n + h f(x_n, y_n) \]

where \( y' = f(x, y) \). In our case, \( f(x, y) = 1 + 3x + 2y \).

#### Computation Steps
To compute the desired values, we will follow these steps:

1. **Initial Step:**
   \[
   y_0 = y(0) = 0
   \]
   Plugging in \( x_0 = 0 \) and \( y_0 = 0 \) into the differential equation, we get:
   \[
   y' = 1 + 3(0) + 2(0) = 1
   \]
   Using Euler's formula for the next step:
   \[
   y_1 = y_0 + hf(x_0, y_0) = 0 + 0.5 \times 1 = 0.5
   \]

2. **First Step:**
   \[
   x_1 = 0.5, \quad y_1 = 0.5
   \]
   Plugging in \( x_1 = 0.5 \) and \( y_1 = 0.5 \) into the differential equation, we get:
   \[
   y' = 1 + 3(0.5) + 2(0.5) = 3
   \]
   Using Euler's formula for the next step:
   \[
   y_2 = y_1 + hf(x_1, y_1) = 0.5 + 0.5 \times 3 = 2
   \]

3. **Second Step
Transcribed Image Text:### Euler's Method for Solving Initial-Value Problems This section will guide you through using Euler's method to compute approximate solutions for an initial-value problem. #### Problem Statement We are given the differential equation: \[ y' = 1 + 3x + 2y \] with the initial condition: \[ y(0) = 0 \] Using Euler's method with a step size \( h = 0.5 \), we need to compute the approximate \( y \)-values \( y_1, y_2, y_3 \), and \( y_4 \). Euler's method formula can be written as: \[ y_{n+1} = y_n + h f(x_n, y_n) \] where \( y' = f(x, y) \). In our case, \( f(x, y) = 1 + 3x + 2y \). #### Computation Steps To compute the desired values, we will follow these steps: 1. **Initial Step:** \[ y_0 = y(0) = 0 \] Plugging in \( x_0 = 0 \) and \( y_0 = 0 \) into the differential equation, we get: \[ y' = 1 + 3(0) + 2(0) = 1 \] Using Euler's formula for the next step: \[ y_1 = y_0 + hf(x_0, y_0) = 0 + 0.5 \times 1 = 0.5 \] 2. **First Step:** \[ x_1 = 0.5, \quad y_1 = 0.5 \] Plugging in \( x_1 = 0.5 \) and \( y_1 = 0.5 \) into the differential equation, we get: \[ y' = 1 + 3(0.5) + 2(0.5) = 3 \] Using Euler's formula for the next step: \[ y_2 = y_1 + hf(x_1, y_1) = 0.5 + 0.5 \times 3 = 2 \] 3. **Second Step
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