Scores turned In by an amateur golfer at a golf course during 2017 and 2018 are as follows. 2017 Season 75 79 80 78 76 74 76 78 2018 Season 71 76 78 86 81 72 72 80 (a) Use the mean and standard deviation to evaluate the golfer's performance over the two-year period. Compute the mean and standard deviation for the 2017 season. (Round the standard deviation to two decimal places. mean 77 sample standard deviation 1.94 Compute the mean and standard deviation for the 2018 season. (Round the standard deviation to two decimal places.) mean 77 sample standard deviation 4.92

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How do I solve for the sample standard deviation ?
Scores turned In by an amateur golfer at a golf course during 2017 and 2018 are as follows.
2017 Season
75
79
80
78 76
74
76
78
2018 Season
71 76
78 86 81
72
72 80
(a) Use the mean and standard deviation to evaluate the golfer's performance over the two-year period.
Compute the mean and standard deviation for the 2017 season. (Round the standard deviation to two decimal places.
mean
77
sample standard deviation
1.94
Compute the mean and standard deviation for the 2018 season. (Round the standard deviation to two decimal places.)
mean
77
sample standard deviation
4.92
Transcribed Image Text:Scores turned In by an amateur golfer at a golf course during 2017 and 2018 are as follows. 2017 Season 75 79 80 78 76 74 76 78 2018 Season 71 76 78 86 81 72 72 80 (a) Use the mean and standard deviation to evaluate the golfer's performance over the two-year period. Compute the mean and standard deviation for the 2017 season. (Round the standard deviation to two decimal places. mean 77 sample standard deviation 1.94 Compute the mean and standard deviation for the 2018 season. (Round the standard deviation to two decimal places.) mean 77 sample standard deviation 4.92
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