Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with $ \mu = 111 $ and $ \sigma = 15 $.(a) What proportion of children aged 13 to 15 years old have scores on this test above 97? (NOTE: Please enter your answer in decimal form. For example, 45.23% should be entered as 0.4523.)Answer: [ ](b) Enter the score which marks the lowest 25 percent of the distribution.Answer: [ ](c) Enter the score which marks the highest 10 percent of the distribution.Answer: [ ]

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Answered: Scores on a certain intelligence test…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose that 9% of all athletes in a sport use a banned drug. A test is available that detects 94% of athletes who use the drug. But the test also gives a positive result for 8% of those who do not use the drug. What percent of athletes who test positive for the drug are actually using the drug? Answer: 77.28 %
A parent comes to you and asks the difference between percent correct and the national percentile rank on an achievement test. What do you tell the parent?
Approximately 1.4% is not correct
When the Standard Score = -2, what is the percentile of the raw Score? 2nd O 14th 16th 34th 84th
You wish to determine which of two brands of TVs is more expensive. You conduct the following sample, which suggests that Orion TVs are more expensive: Orion: ā = $318, sª = 12.6, п — 30 Luna: ā = $313, 8z = 15.1, n = 25 Define your variable: O Let p be the proprotion Orion TVs in the sample that cost more than Luna TVs. OLet u be the mean price of TVs, in dollars Let mu the mean price of Orion TVs, in dollars. Let u be the mean price of sampled TVs, in dollars. Write your hypotheses: Be sure to chose Group 1 to have the larger sample mean. Но: Opi – P2 = 0 O pi – P2 = 318 – 313 Ο μ-μ 5 µi - µ2 = 0 HA: Hi – µ2 > 0 O ui – u2 < 0 µi – µ2 = 5 Opi - - P2 = 318 – 313
A sample of students having an online class before noon was taken. They were asked "Are you still in your pajamas?" The following frequency table summarizes the responses Valid 0.32 no Integer, decimal, or E notation allowed yes Total What is the proportion for those still in pajamas? (use 3 decimal places.) Frequency 42 32 74 pajamas Percent 56.8 43.2 100.0 Valid Percent 56.8 43.2 100.0 Cumulative Percent 56.8 100.0 ...
Statistics Canada conducts an annual survey to estimate the proportion of Canadians aged 20 - 24 years of age who are smokers. The most recent application of the Canadian Tobacco Monitoring Survey involved a random sample of n=496 Canadians aged 20 to 24 years of age. Each was asked for the smoking status. The number of 20 to 24 year-olds sampled who indicated they were smokers was 333.(a) Compute the sample proportion. Use at least four decimals in your answer.p^= __________ (b) Using your answer in (a), find a 97% confidence interval for pnow, the current proportion of 20 to 24 year old Canadians who are smokers, by Bootstrapping 1000 samples. Use the seed 3994 to ensure that R-Studio "randomly" samples the same "random" samples as this question will expect.You can do this by including the code, you can copy it into your R-Studio to bootstrap your samples.RNGkind(sample.kind = "Rejection");set.seed(3994);B=do(1000) * mean(resample(c(rep(1,333),rep(0,496-333)), 496));Use at least four…
The 20 scores below were recorded from a math test: 75, 64, 82, 68, 75, 73, 68, 78, 80, 97, 85, 68, 62, 52, 77, 85, 90, 83, 68, 82 Using the 20 math score, neatly construct a relative frequency histogram.
The distances golf balls travel under laboratory testing conditions are normally distributed. The mean is 312 yards. The probability the golf ball travels further than 319 yards is 0.28. Find the probability a randomly selected golf ball travels between 305 yards and 319 yards. Express the answer as a decimal value rounded to the nearest hundredth.

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