Scores for a common standardized college aptitude test are normally distributed with a mean of 508 and a standard deviation of 109. Randomly selected students are given a Test Preparation Course before taking this test. Assume, for sake of argument, that the preparation course has no effect. If 1 student is randomly selected, find the probability that their score is at least 557.1. P(X> 557.1) = Enter your answer as a number accurate to 4 decimal places. If 16 students are randomly selected, find the probability that their mean score is at least 557.1. P(X > 557.1) = Enter your answer as a number accurate to 4 decimal places. Assume that any probability less than 5% is sufficient evidence to conclude that the preparation course does help students perform better on the test. If the random sample of 16 students does result in a mean score of 557.1, is there strong evidence to support the claim that the course is actually effective? O No. The probability indicates that it is possible by chance alone to randomly select a group of students with a mean as high as 557.1. Yes. The probability indicates that it is (highly?) unlikely that by chance, a randomly selected group of students would get a mean as high as 557.1.

MATLAB: An Introduction with Applications
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Hello, can you please help with this problem and explain. I assume this is normalcdf of the calculator? would the excel formula be NORMSDIST or NORM.S.DIST? Thank you! 

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Per the warning...This is not a graded assignment, I found this on the internet for practice...

Scores for a common standardized college aptitude test are normally distributed with a mean of 508 and a
standard deviation of 109. Randomly selected students are given a Test Preparation Course before taking
this test. Assume, for sake of argument, that the preparation course has no effect.
If 1 student is randomly selected, find the probability that their score is at least 557.1.
P(X> 557.1) =
Enter your answer as a number accurate to 4 decimal places.
If 16 students are randomly selected, find the probability that their mean score is at least 557.1.
P(X > 557.1) =
Enter your answer as a number accurate to 4 decimal places.
Assume that any probability less than 5% is sufficient evidence to conclude that the preparation course
does help students perform better on the test. If the random sample of 16 students does result in a mean
score of 557.1, is there strong evidence to support the claim that the course is actually effective?
O No. The probability indicates that it is possible by chance alone to randomly select a group of
students with a mean as high as 557.1.
Yes. The probability indicates that it is (highly?) unlikely that by chance, a randomly selected group
of students would get a mean as high as 557.1.
Transcribed Image Text:Scores for a common standardized college aptitude test are normally distributed with a mean of 508 and a standard deviation of 109. Randomly selected students are given a Test Preparation Course before taking this test. Assume, for sake of argument, that the preparation course has no effect. If 1 student is randomly selected, find the probability that their score is at least 557.1. P(X> 557.1) = Enter your answer as a number accurate to 4 decimal places. If 16 students are randomly selected, find the probability that their mean score is at least 557.1. P(X > 557.1) = Enter your answer as a number accurate to 4 decimal places. Assume that any probability less than 5% is sufficient evidence to conclude that the preparation course does help students perform better on the test. If the random sample of 16 students does result in a mean score of 557.1, is there strong evidence to support the claim that the course is actually effective? O No. The probability indicates that it is possible by chance alone to randomly select a group of students with a mean as high as 557.1. Yes. The probability indicates that it is (highly?) unlikely that by chance, a randomly selected group of students would get a mean as high as 557.1.
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