Scheduling a Class (Intermediate above) You are an administrator for the Kulliyyah and is assigned the task to schedule a set of classes for a given day. Unfortunately, there is only one lecture hall and therefore, two classes cannot run at the same time. This is usually an easy task, however, there are some criteria that you would have to consider. The criteria are as follows: · Each class has a duration class time. · Higher level courses has higher priority than other low level courses. · Some lecturers prefer to have morning classes instead of the afternoon classes because they come to the office much earlier than other lecturers so they should be scheduled earlier. Your job is to propose the best scheduling based on this criteria. To do this, you will write a C++ program that will first sort the classes by lecturer arrive time and then by course levels. Lecturers arriving early, can start first, but if they arrive at the same time, the higher level course will go first. Course 3301 for example, has higher priority than 3300 and 1100. You will need a struct, to be defined, as the one given below. struct Course { int ccode; // course code // class duration in military hours, 2 hours is 200 and so on int duration; //prefered start time 800 for 8am and 1200 for 12pm int lecture_arrive_time; }; Your program should output the course code with the time a class starts. We assume military time and the day starts at 800 hours and finishes at 2200 hours. If the class exceeds 2200 hours, your program should indicate that the course cannot be schedule. We also assume that there is no allocated lunch or dinner breaks. Your program should ask for the input from the user. The input ends with 999 to indicate that there are no more classes to be scheduled. Please enter class details. 3203 100 1500 1103 100 1500 2201 300 800 2203 100 1500 3401 200 800 1201 100 1500 999 The output should be the following: 3401 starts at 800 ends at 1000 2201 starts at 1000 ends at 1300 3203 starts at 1500 ends at 1600 2203 starts at 1600 ends at 1700 1201 starts at 1700 ends at 1800 1103 starts at 1800 ends at 1900 To help you get started, you are given with a code snippet to write your code. #include using namespace std; struct Course { int ccode; // course code int duration; // class duration in military hours, so 2 hours is 200 an so on int lecture_arrive_time; //prefered start time 800 for 8am and 1200 for 12pm }; void print_sched(Course c[],int); void class_sort(Course c[],int); int main() { int input=0,i=0; Course classes[100]; cout << "Please enter class details:" << endl; cin >> input; while (input != 999){ classes[i].ccode = input; cin >> classes[i].duration; cin >> classes[i].lecture_arrive_time; i++; cin >> input; } class_sort(classes, i); print_sched(classes, i); }
Scheduling a Class (Intermediate above)
You are an administrator for the Kulliyyah and is assigned the task to schedule a set of classes for a given day. Unfortunately, there is only one lecture hall and therefore, two classes cannot run at the same time. This is usually an easy task, however, there are some criteria that you would have to consider. The criteria are as follows:
· Each class has a duration class time.
· Higher level courses has higher priority than other low level courses.
· Some lecturers prefer to have morning classes instead of the afternoon classes because they come to the office much earlier than other lecturers so they should be scheduled earlier.
Your job is to propose the best scheduling based on this criteria. To do this, you will write a C++
You will need a struct, to be defined, as the one given below.
struct Course
{
int ccode; // course code
// class duration in military hours, 2 hours is 200 and so on
int duration;
//prefered start time 800 for 8am and 1200 for 12pm
int lecture_arrive_time;
};
Your program should output the course code with the time a class starts.
We assume military time and the day starts at 800 hours and finishes at 2200 hours. If the class exceeds 2200 hours, your program should indicate that the course cannot be schedule. We also assume that there is no allocated lunch or dinner breaks.
Your program should ask for the input from the user. The input ends with 999 to indicate that there are no more classes to be scheduled.
Please enter class details.
3203 100 1500
1103 100 1500
2201 300 800
2203 100 1500
3401 200 800
1201 100 1500
999
The output should be the following:
3401 starts at 800 ends at 1000
2201 starts at 1000 ends at 1300
3203 starts at 1500 ends at 1600
2203 starts at 1600 ends at 1700
1201 starts at 1700 ends at 1800
1103 starts at 1800 ends at 1900
To help you get started, you are given with a code snippet to write your code.
#include <iostream>
using namespace std;
struct Course
{
int ccode; // course code
int duration; // class duration in military hours, so 2 hours is 200 an so on
int lecture_arrive_time; //prefered start time 800 for 8am and 1200 for 12pm
};
void print_sched(Course c[],int);
void class_sort(Course c[],int);
int main()
{
int input=0,i=0;
Course classes[100];
cout << "Please enter class details:" << endl;
cin >> input;
while (input != 999){
classes[i].ccode = input;
cin >> classes[i].duration;
cin >> classes[i].lecture_arrive_time;
i++;
cin >> input;
}
class_sort(classes, i);
print_sched(classes, i);
}
** you will need to implement the functions **
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