Scenario 2 Herman the human cannonball is launched from level ground at different angles above the horizontal with an initial velocity of 26m/s. Determine the following information.show work below. Think about.how will I find these: write a general equation for each above it Angle Time Spent in Air Max Height Range 15° 40° 60° 75° 90° How does the range compare for the complimentary angles? How does the time spent in the air compare for the complimentary angles?

Q: (a) What are the coordinates of the initial position of the stone? kg- Yo (b) What are the…

A: We will use kinematic equations of motion to answer the questions. The steps are as follows.

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A: initial velocity = V0= 45 m/s angle = 60 degrees

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Q: long is it A soccer ball is kicked with an initial velocity of 31.0 m/s at an angle horizon. How far…

A: θ= 65°v=31.0 m/s

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Q: A projectile is launched horizontally with a speed of 13.0 m/s from the top of a 77.0m cliff. How…

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A: The expression for the time taken is given by

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Q: a) What is the horizontal component of the initial velocity for 45° and 60° b) What is the vertical…

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Q: Q3/ A mator boat is heading due east the river at 15 Km/hr Current South the angle where is at in…

A: Boat v =15 km/hr Current v = 5 km/hr angle =70  degrees + 90=160 degrees

Q: 22, IA man crosses a river through shortest distance D as given in the figure. VR is velocity of…

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A: Give that velocity v= 25 m/s angle θ=20°

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A: Ux= 17.3 m/s  Uy= 10 m/s  Height of the ball when it crosses horizontal range is about 22m ?

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Q: The trajectory of water is shown in the following figure. Determine at what point, relative to point…

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A: initial height = 1.76 m Launch angle = 30oInitial speed = 22 ms

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Q: 5. A projectile is shot off a 200 m cliff at a 45° angle to the ground with an initial speed of 120.…

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Q: 3. A golf ball is launched from the roof of a school with a velocity 20.0 m/s at an angle of 30.0°…

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Q: 1. A ball is projected with a velocity of 20 m/s at an angle of 35 degrees from the top of a 75-m…

A: Given, u= 20m/s theta= 35° at height h, v= 0 Vertical component of projection velocity is given by,…

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Q: A fired a cannon ball with a speed of 18.5 m/s at an angle of 70.0° above the horizon. 1) What's the…

A: Givenu=18.5 m/sθ=70o1)formula for maximum height h,h=u2sin2θ2g  =(18.5)2sin2(70)2×9.80  =15.42 m…

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A: using projectile motion equations,

Q: When a projectile is at the top/apex of its motion, how are the velocity, , and acceleration, ,…

A: Solution:

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A: Given that  Initial velocity of the projectile is  u=35 MS Launch angle is  θ=350

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Projectile Motion