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Scenario 1 Your boss, Melon Usk, wants you to determine the acceleration of his new car. The details of the car are as follows: The car's total mass is 1500 kg The motor outputs a constant torque of 300 Nm The drive train has a gear ratio of 10:1 to the drive axle Prior to any gearing, the motor and drivetrain have a moment of inertia of 0.5 kg m². The four tires are 0.6 m in diameter. A single set of final gear, drive axial, and tire has combined moment of inertia of 0.6 kg m². Not knowing how to proceed, you e-mail your favourite ex-instructor, Frank. He is very busy but draws you the following: ● ● Motor FT+ IM = 0.5 kg m² TIN = 300Nm TIN Final Gear + Wheel Wheel RG P Rw Final Gear Fw Iw = 4(0.6 kg m²) = 2.4kg. m² RG = 10R Rw = 0.3m Car Fw m = 1500kg x Frank also notes the following: • You can treat all four tires, axels, and final gears as a single entity. The moments of inertia will add together but the radius will remain the same. You do not need to know the complex shape of the motor or transmission. Instead, just treat everything before the first gear as a single entity. Likewise, you can treat the final gears, the drive axels, and the wheels as a single entity. Find: a) The acceleration of the car treating the drive train and tires as rigid bodies. b) The acceleration of car if you treated it as a particle in its entirety (i.e. you disregard moments of inertia) c) The percentage difference between the acceleration of a) with respect to b)

Scenario 1 Your boss, Melon Usk, wants you to determine the acceleration of his new car. The details of the car are as follows: The car's total mass is 1500 kg The motor outputs a constant torque of 300 Nm The drive train has a gear ratio of 10:1 to the drive axle Prior to any gearing, the motor and drivetrain have a moment of inertia of 0.5 kg m². The four tires are 0.6 m in diameter. A single set of final gear, drive axial, and tire has combined moment of inertia of 0.6 kg m². Not knowing how to proceed, you e-mail your favourite ex-instructor, Frank. He is very busy but draws you the following: ● ● Motor FT+ IM = 0.5 kg m² TIN = 300Nm TIN Final Gear + Wheel Wheel RG P Rw Final Gear Fw Iw = 4(0.6 kg m²) = 2.4kg. m² RG = 10R Rw = 0.3m Car Fw m = 1500kg x Frank also notes the following: • You can treat all four tires, axels, and final gears as a single entity. The moments of inertia will add together but the radius will remain the same. You do not need to know the complex shape of the motor or transmission. Instead, just treat everything before the first gear as a single entity. Likewise, you can treat the final gears, the drive axels, and the wheels as a single entity. Find: a) The acceleration of the car treating the drive train and tires as rigid bodies. b) The acceleration of car if you treated it as a particle in its entirety (i.e. you disregard moments of inertia) c) The percentage difference between the acceleration of a) with respect to b)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Scenario 1 Your boss, Melon Usk, wants you to determine the acceleration of his new car. The details of the car are as follows: The car's total mass is 1500 kg The motor outputs a constant torque of 300 Nm The drive train has a gear ratio of 10:1 to the drive axle Prior to any gearing, the motor and drivetrain have a moment of inertia of 0.5 kg m². The four tires are 0.6 m in diameter. A single set of final gear, drive axial, and tire has combined moment of inertia of 0.6 kg m². Not knowing how to proceed, you e-mail your favourite ex-instructor, Frank. He is very busy but draws you the following: ● ● ● ● ● ● Motor ● FT+ IM = 0.5 kg. m² TIN = 300Nm TIN Final Gear + Wheel Wheel RG Final Gear C Rw Fw Iw = 4(0.6 kg m²) = 2.4kg. m² RG = 10R Rw = 0.3m Car Fw m = 1500kg y x Frank also notes the following: You can treat all four tires, axels, and final gears as a single entity. The moments of inertia will add together but the radius will remain the same. You do not need to know the complex shape of the motor or transmission. Instead, just treat everything before the first gear as a single entity. Likewise, you can treat the final gears, the drive axels, and the wheels as a single entity. Find: a) The acceleration of the car treating the drive train and tires as rigid bodies. b) The acceleration of car if you treated it as a particle in its entirety (i.e. you disregard moments of inertia) c) The percentage difference between the acceleration of a) with respect to b)
Transcribed Image Text:Scenario 1 Your boss, Melon Usk, wants you to determine the acceleration of his new car. The details of the car are as follows: The car's total mass is 1500 kg The motor outputs a constant torque of 300 Nm The drive train has a gear ratio of 10:1 to the drive axle Prior to any gearing, the motor and drivetrain have a moment of inertia of 0.5 kg m². The four tires are 0.6 m in diameter. A single set of final gear, drive axial, and tire has combined moment of inertia of 0.6 kg m². Not knowing how to proceed, you e-mail your favourite ex-instructor, Frank. He is very busy but draws you the following: ● ● ● ● ● ● Motor ● FT+ IM = 0.5 kg. m² TIN = 300Nm TIN Final Gear + Wheel Wheel RG Final Gear C Rw Fw Iw = 4(0.6 kg m²) = 2.4kg. m² RG = 10R Rw = 0.3m Car Fw m = 1500kg y x Frank also notes the following: You can treat all four tires, axels, and final gears as a single entity. The moments of inertia will add together but the radius will remain the same. You do not need to know the complex shape of the motor or transmission. Instead, just treat everything before the first gear as a single entity. Likewise, you can treat the final gears, the drive axels, and the wheels as a single entity. Find: a) The acceleration of the car treating the drive train and tires as rigid bodies. b) The acceleration of car if you treated it as a particle in its entirety (i.e. you disregard moments of inertia) c) The percentage difference between the acceleration of a) with respect to b)
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