Say we have a continuous random variable X. Let ƒ(x) = c(1 + x²) for support S = [0,1] and c being a constant. What value of c will make this a valid density function? Round to the nearest 2nd decimal place, x.xx

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### Continuous Random Variable Density Function

We consider a continuous random variable \( X \).

Define the probability density function \( f(x) = c(1 + x^2) \) over the support \( S_x = [0, 1] \), with \( c \) being a constant.

The problem is to determine the value of \( c \) that will make \( f(x) \) a valid density function.

To find \( c \), the integral of \( f(x) \) over the support \( S_x \) must equal 1:
\[ \int_{0}^{1} f(x) \, dx = 1. \]

Given \( f(x) = c(1 + x^2) \):
\[ \int_{0}^{1} c(1 + x^2) \, dx = 1. \]

Solving this integral will give us the required value of \( c \).

Round the value of \( c \) to the nearest 2nd decimal place, \( x.xx \).
Transcribed Image Text:### Continuous Random Variable Density Function We consider a continuous random variable \( X \). Define the probability density function \( f(x) = c(1 + x^2) \) over the support \( S_x = [0, 1] \), with \( c \) being a constant. The problem is to determine the value of \( c \) that will make \( f(x) \) a valid density function. To find \( c \), the integral of \( f(x) \) over the support \( S_x \) must equal 1: \[ \int_{0}^{1} f(x) \, dx = 1. \] Given \( f(x) = c(1 + x^2) \): \[ \int_{0}^{1} c(1 + x^2) \, dx = 1. \] Solving this integral will give us the required value of \( c \). Round the value of \( c \) to the nearest 2nd decimal place, \( x.xx \).
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