SAT scores are known to follow a normal distribution with a standard deviation of 100 points. Test the claim that the population mean SAT score at ACME High School is different than at ACE High School. A random sample of 33 ACME students yields ãi = 982 and a random sample of 33 ACE yields 2 = 972. Use a = 0.10, and let ACME be Population 1. 1. The sample size requirement for this test is: O Sample sizes must both be at least thirty since this is a T-test O Sample sizes must both be at least thirty since this is a Z-test ON/A since the populations are normally distributed ON/A since this is a Z-test The bypotbeses are:

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The Degrees of Freedom are
O33
ON/A; this is a Z-test
O 32
3. The STS (round to 3 decimals) is:
The P-value (round to 4 decimals) is:
4. The decision at a = 0.10 is:
O Reject Ho since P > a
O Do not reject Ho since P< a
O Do not reject Ho since P > a
Reject Ho since P< a
The conclusion is:
O There is insufficient evidence to reject the claim that the mean salary at ACME is different than at
ACE
O There is sufficient evidence to reject the claim that the mean SAT score at ACME is different than at
ACE
O There is insufficient evidence to support the claim that the mean SAT score at ACME is different than
at ACE
O There is sufficient evidence to support the claim that the mean SAT score at ACME is different than
at ACE
Transcribed Image Text:The Degrees of Freedom are O33 ON/A; this is a Z-test O 32 3. The STS (round to 3 decimals) is: The P-value (round to 4 decimals) is: 4. The decision at a = 0.10 is: O Reject Ho since P > a O Do not reject Ho since P< a O Do not reject Ho since P > a Reject Ho since P< a The conclusion is: O There is insufficient evidence to reject the claim that the mean salary at ACME is different than at ACE O There is sufficient evidence to reject the claim that the mean SAT score at ACME is different than at ACE O There is insufficient evidence to support the claim that the mean SAT score at ACME is different than at ACE O There is sufficient evidence to support the claim that the mean SAT score at ACME is different than at ACE
O Question 25
SAT scores are known to follow a normal distribution with a standard deviation of 100 points. Test the
claim that the population mean SAT score at ACME High School is different than at ACE High School. A
random sample of 33 ACME students yields 1 = 982 and a random sample of 33 ACE yields 2 = 972.
Use a = 0.10, and let ACME be Population 1.
1. The sample size requirement for this test is:
O Sample sizes must both be at least thirty since this is a T-test
O Sample sizes must both be at least thirty since this is a Z-test
ON/A since the populations are normally distributed
O N/A since this is a Z-test
The hypotheses are:
O Ho:µi 2 p2; Ha: µ1 < µ2
O Ho:p1 < p2; Ha:p1 > p2
O Ho: µ1 = p2; Ha:µ1 # µ2
O Ho: µi < p2; Ha:µ1 > µ2
O Ho:pi 2 p2; Ha:pi < p2
O Ho:p1 = p2; Ha:pı # p2
2. This is a C leftO rightO two tailed test and the distribution used is
OZ since both o values are known
OT since both o values are not known
OZ since testing two proportions
Transcribed Image Text:O Question 25 SAT scores are known to follow a normal distribution with a standard deviation of 100 points. Test the claim that the population mean SAT score at ACME High School is different than at ACE High School. A random sample of 33 ACME students yields 1 = 982 and a random sample of 33 ACE yields 2 = 972. Use a = 0.10, and let ACME be Population 1. 1. The sample size requirement for this test is: O Sample sizes must both be at least thirty since this is a T-test O Sample sizes must both be at least thirty since this is a Z-test ON/A since the populations are normally distributed O N/A since this is a Z-test The hypotheses are: O Ho:µi 2 p2; Ha: µ1 < µ2 O Ho:p1 < p2; Ha:p1 > p2 O Ho: µ1 = p2; Ha:µ1 # µ2 O Ho: µi < p2; Ha:µ1 > µ2 O Ho:pi 2 p2; Ha:pi < p2 O Ho:p1 = p2; Ha:pı # p2 2. This is a C leftO rightO two tailed test and the distribution used is OZ since both o values are known OT since both o values are not known OZ since testing two proportions
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