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Sara solved the equation -5=x-√√x+11 as follows. -5 = x-√√x+11 √√x+11 = x+5 x+11= x²+10x +25 0x2+9x + 14 0 = (x+7Xx+2) x = -7, x=-2 The extraneous root(s) introduced by Sara is/are Select one: a. -7 b. -2 and -7 c. no extraneous root was introduced d. -2

Sara solved the equation -5=x-√√x+11 as follows. -5 = x-√√x+11 √√x+11 = x+5 x+11= x²+10x +25 0x2+9x + 14 0 = (x+7Xx+2) x = -7, x=-2 The extraneous root(s) introduced by Sara is/are Select one: a. -7 b. -2 and -7 c. no extraneous root was introduced d. -2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Sara solved the equation -5=x-√√x+11 as follows. -5 = x-√√x+11 √x+11 = x+5 x+11= x²+10x +25 0x²+9x + 14 0= 0 = (x+7Xx+2) x = -7, x = -2 The extraneous root(s) introduced by Sara is/are Select one: a. -7 b. -2 and -7 c. no extraneous root was introduced Od. -2
Transcribed Image Text:Sara solved the equation -5=x-√√x+11 as follows. -5 = x-√√x+11 √x+11 = x+5 x+11= x²+10x +25 0x²+9x + 14 0= 0 = (x+7Xx+2) x = -7, x = -2 The extraneous root(s) introduced by Sara is/are Select one: a. -7 b. -2 and -7 c. no extraneous root was introduced Od. -2
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