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Sanity check - For ideal gas, AS = Sf - S¡ = nR ln / +nCv In Consider a process from (V₁, P₁) to (V₂, P₂) where P₁V₁Y = P₂V₂, explicitly show that AS = 0

Sanity check - For ideal gas, AS = Sf - S¡ = nR ln / +nCv In Consider a process from (V₁, P₁) to (V₂, P₂) where P₁V₁Y = P₂V₂, explicitly show that AS = 0

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Sanity check - For ideal gas, AS = S₁ − S¡ = nR In ¼/+nCy In. Consider a process from (V₁, P₁) to (V₂, P₂2) where P₁V₁Y = P₂V, explicitly show that AS = 0 1
Transcribed Image Text:Sanity check - For ideal gas, AS = S₁ − S¡ = nR In ¼/+nCy In. Consider a process from (V₁, P₁) to (V₂, P₂2) where P₁V₁Y = P₂V, explicitly show that AS = 0 1
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