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Civil Engineering
Sand: WT Ysat = 19 kN/m³ Ydry = 17 kN/m³ 3.5 m Sand: Ysat = 20 kN/m³ 4.5 m Ydry = 18 kN/m³ Ysat = 20 kN/m³ eo= 0.9 Clay: = Cc 0.36 Cr 0.12 = OCR = 1 6.0 m Sand: Ysat = 19 kN/m³ 2.0 m BEDROCK

Sand: WT Ysat = 19 kN/m³ Ydry = 17 kN/m³ 3.5 m Sand: Ysat = 20 kN/m³ 4.5 m Ydry = 18 kN/m³ Ysat = 20 kN/m³ eo= 0.9 Clay: = Cc 0.36 Cr 0.12 = OCR = 1 6.0 m Sand: Ysat = 19 kN/m³ 2.0 m BEDROCK

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A pressure increase of 250 kPa is imposed across a wide region above the depicted soil profile. The clay stratum is initially under normal consolidation and has a coefficient of consolidation (cv) of 0.002 cm2/s. The groundwater level sits 3.5 meters beneath the soil surface. Determine the settlement of the clay layer, in millimeters, 40 days following the application of the pressure increase. noted that The final settlement at the end of primary consolidation is equal to 515 mm. 

Sand: WT Ysat = 19 kN/m³ Ydry = 17 kN/m³ 3.5 m Sand: Ysat = 20 kN/m³ 4.5 m Ydry = 18 kN/m³ Ysat = 20 kN/m³ eo= 0.9 Clay: = Cc 0.36 Cr 0.12 = OCR = 1 6.0 m Sand: Ysat = 19 kN/m³ 2.0 m BEDROCK
Transcribed Image Text:Sand: WT Ysat = 19 kN/m³ Ydry = 17 kN/m³ 3.5 m Sand: Ysat = 20 kN/m³ 4.5 m Ydry = 18 kN/m³ Ysat = 20 kN/m³ eo= 0.9 Clay: = Cc 0.36 Cr 0.12 = OCR = 1 6.0 m Sand: Ysat = 19 kN/m³ 2.0 m BEDROCK
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