SampleSuccesses 120N 600ResultZ Estimate of a ProportionSuccesses120600SE0.0163Lower Limit0.168Upper Limit0.232Interval0.2 + 0.032a) Using the technology output given, write out the 95% confidence interval for the true populationproportion of people preferes candidate A.

Sample proportion is calculated by the dividing the number of favorable cases or success by total…

Answered: Sample Successes 120 N 600 Result Z…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question Help ▼ 7.2.7-1 Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value t/2, (b) find the critical value za/2, or (c) 40- state that neither the normal distribution nor the t distribution applies. 30- The confidence level is 90%, o = 3775 thousand dollars, and the histogram of 64 player salaries (in thousands of dollars) of football players on a team is as shown. 20- 10- 0- 4000 8000 1200 16000 2000 Salary (thousands of dollars) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. ta/2= (Round to two decimal places as needed.) O B. Za/2= (Round to two decimal places as needed.) OC. Neither the normal distribution nor the t distribution applies.
1/12 part b construct a 99% confidence interval about... we are 99% confident that the main differences between_and_. Round to two decimal places as needed. Use ascending order.
10:09 5G 4 AA A mathxl.com 2021SP Elementary Statistical Methods (MATH-1342-32402) Adrian Gonzalez 04/11/21 10:09 PM Here are summary statistics for randomly selected weights of newborn girls: n = 213, x = 31.3 hg, s = 6.3 hg. Construct a confidence interval estimate of the mean. Use a 95% confidence level. Are these results very different from the confidence interval 30.2 hg < u< 32.0 hg with only 19 sample values, x = 31.1 hg, and s = 1.8 hg? What is the confidence interval for the population mean u? hg < u< hg (Round to one decimal place as needed.) Are the results between the two confidence intervals very different? O A. No, because the confidence interval limits are similar. O B. Yes, because the confidence interval limits are not similar. C. No, because each confidence interval contains the mean of the other confidence interval. O D. Yes, because one confidence interval does not contain the mean of the other confidence interval. Click to select your answer(s).
data: FieldA and Fields af- 34.751, p-value e.001292 alternative hypothesis: true difference in means is not equal to 0 95 percent conf dence interval: sample estimates: mean of x mean of 13.98803 11.02686 Q. Based on the summary statistics calculate the missing t test statistic from the R output: t statistic = 3.583 Q. Give the set up for the 95% confidence interval for the difference in averages. Use the degrees of freedom from the R output (round down). Estimate ± Critical Value × Standard Error - 14 2.042 0.701 Q. Make a conclusion based on the previous results. There is convincing evidence the average percent of water by volume in the soil between Field A and Field B differs. Based on the p-value, the test rejects * the null hypothesis. The 95% confidence interval and point estimate indicate the Field A has more average percent by volume than Field B.
Find the smallest sample size needed to estimate the mean number ofcomputers sold by a store to within 4 computers and a confidence interval of 90% if:The sample has s = 18 s =E =α =α⁄2 =zα⁄2 = n = You need at least _____ computers in the sample to estimatethe population mean number of computers sold with a margin oferror of _______ computers with a ______ confidence.
1,222 1,271 1,250 1,264 1,268 1,316 1,275 1,317 1,275 Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (Round your answers to the nearest whole number.) lower limit Upper limit
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Quescion 3 A random sample of 21 colleges was taken. The mean rate of graduation within four years was 78% with a margin of error of 5.1%. The distribution of graduation rates is Normal. a) Based on this, give the confidence interval for the true mean rate of graduation. Give your answers rounded to two decimal places % < µ < b) Can we reject a population mean percentage of 85.1% on the basis of these numbers? Explain. O Yes, reject 85.1%. Since 85.1% is in the interval, it is not possible the population graduation rate is 85.1%. O No, do not reject 85.1%. Since 85.1% is not in the interval, it is possible the population graduation rate is 85.1%. O No, do not reject 85.1%. Since 85.1% is in the interval, it is possible the population graduation rate is 85.1%. O Yes, reject 85.1%. Since 85.1% is not in the interval, it is not possible the population graduation rate is 85.1%. Submit Question

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Sample Successes 120 N 600 Result Z Estimate of a Proportion Successes 120 600 SE 0.0163 Lower Limit 0.168 Upper Limit 0.232 Interval 0.2 ±0.032 a) Using the technology output given, write out the 95% confidence interval for the true population proportion of people preferes candidate A.