sample standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal Body Temperatures (in °F) of Adult Males 98.1 98.0 98.4 97.2 99.2 97.9 97.7 98.2 96.5 97.1 96.6 97.8 97.8 99.2 97.0 97.9 97.1 99.2 97.1 97.7
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- Use the data in the table to the right to answer the following questions. Weights (g) of a Sample Bag of Candy Red Blue Brown Green Yellow 0.964 0.793 0.784 0.814 0.966 0.708 0.991 0.845 0.771 0.733 Find the sample proportion of candy that are red. 0.747 0.886 0.782 0.793 0.882 0.766 0.766 0.919 0.923 0.975 0.849 The proportion of red candy = 0.958 0.762 0.712 0.938 0.752 0.915 (Type an integer or decimal rounded to three decimal places as needed.) 0.822 0.844 0.733 0.781 0.976 0.955 0.827 0.939 0.818 0.805 0.812 0.725 0.966 0.815 0.854 0.915What is the standard deviation?Find the 20 % trimmed mean of the following data. If necessary, round to one more decimal place than the largest number of decimal places given in the data. Rate of Fatal Alcohol Impaired Car Crashes per 100 Million Vehicle Miles of Travel 0.34 0.34 0.33 0.54 0.56 0.64 0.66 0.29 0.30 0.33 0.51 0.52 Answer How to enter your answer (opens in new window) 0.40 0.41 0.45 0.46 0.70 0.72 0.74 0.78 Tables Copy Da Keyp Keyboard Short
- Find the mean ,median, and mode of the following data. If necessary round one or more decimal place then the largest number of decimal places given in the dataIn the 1992 presidential election, Alaska's 40 election districts averaged 1993 votes per district for President Clinton. The standard deviation was 584. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( b. Is 1993 a population mean or a sample mean? Select an answer v C. Find the probability that a randomly selected district had fewer than 2053 votes for President Clinton. d. Find the probability that a randomly selected district had between 2074 and 2208 votes for President Clinton. e. Find the 95th percentile for votes for President Clinton. Round your answer to the nearest whole number.A distribution has mean 100 and standard deviation 3. What is the largest percent of the data that is guaranteed to be between 40 and 160 93.75 96 97.44 99.75 99.99
- Using technology, find the range and standard deviation, round to one decimals place:The table below gives the number of hours spent watching TV last week by a sample of 24 children. 20 39 34 29 48 84 64 25 75 89 40 57 82 43 62 52 49 59 38 87 49 66 95 17 Range = 78 Standard Deviation = 22.6Find the standard deviation for the following data.Round your answer to 2 decimal places as needed 31,72,84,25,100,18,90,51,47,87Given Samples A and B below, Sample A: 4.9 4.6 4.8 2.7 4.2 2.0 2.1 3.1 5.0 Sample B: 3.2 2.4 3.8 4.2 4.9 5.0 3.6 4.4 2.3 a. Calculate the mean and standard deviation for each sample. Sample A: X A = 0.00; s A = 0.00 Sample B: x B= 0.00 ; s B = 0.00 Round to two decimal places if necessary b. Calculate the coefficient of variation for each sample. Sample A: CV A = 0.00% Sample B: CV B = 0.00% Round to two decimal places if necessary c. Which sample is more variable? Sample A Sample B Neither sample is more variable than the other
- Use the magnitudes (Richter scale) of the 120 earthquakes listed in the accompanying data table. Use technology to find the range, variance, and standard deviation. If another value, 8.00, is added to those listed in the data set, do the measures of variation change much? 3.30 2.77 2.80 1.96 1.69 2.54 2.43 3.44 3.92 1.58 2.87 1.63 2.56 3.95 2.50 2.44 1.82 2.19 2.44 2.99 2.92 2.35 1.98 3.06 2.78 3.86 2.95 2.07 1.86 2.36 2.37 3.46 3.45 1.54 2.54 1.49 2.22 3.06 2.27 3.20 1.96 1.91 2.40 2.95 2.61 1.49 2.16 2.33 1.91 2.70 2.92 1.80 3.66 2.69 1.43 3.60 3.13 2.56 1.54 1.41 2.83 2.85 2.20 1.68 3.18 1.38 1.73 2.37 1.15 2.35 2.46 1.81 2.01 3.00 1.94 2.42 1.85 2.24 2.35 3.22 3.97 2.10 1.48 2.31 2.31 2.62 2.55 2.20 2.77 2.46 2.69 3.57 2.84 2.75 3.26 1.74 4.72 3.23 2.36 2.00 3.83 2.41 2.88 2.67 2.32 2.80 2.80 2.40 3.41 2.34 1.49 2.41 2.45 2.50 2.73 2.44 2.78 2.65 2.68 2.43 Without the extra data value, the range is 3.573.57. (Type an integer or…Using your calculator, find the range and standard deviation, round to two decimals places:The table below gives the number of hours spent watching TV last week by a sample of 24 children. 90 50 46 31 52 83 51 90 72 47 25 57 53 62 65 89 35 49 32 21 77 30 91 13 Range = Standard Deviation =Please help me with this question.